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frez [133]
3 years ago
5

An unknown mass of each of the following substances, initially at 23.0, absorbs 1910 of heat. The final temperature is recorded

as indicated. Find the mass of the substance, given: Pyrex glass (55.5)
Physics
1 answer:
babymother [125]3 years ago
3 0
The data not given here is the specific heat capacity of pyrex glass equal to 0.75(J/g  °C). In this case, heat is equal to mass x specific heat capacity x temperature rise. Temperature difference is then equal to 1910 J / 0.75 J/g  °C / 23 g equal to 110. 75  <span>°C </span>
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Where is the near point of an eye for which a contact lens with a power of +2.55 diopters is prescribed?Where is the far point o
tankabanditka [31]

Answer:

(a). The eye's near point is 68.98 cm from the eye.

(b). The eye's far point is 33.33 cm from the eye.

Explanation:

Given that,

Power = 2.55 D

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Object distance = ∞ for far point

Suppose where is the far point of an eye for which a contact lens with a power of -3.00 D  is prescribed for distant vision?

(a) We need to calculate the focal length

Using formula of power

f =\dfrac{1}{P}

Put the value into the formula

f=\dfrac{100}{2.55}

f=39.21\ cm

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Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{39.21}=\dfrac{1}{v}-\dfrac{1}{-25}

\dfrac{1}{39.21}-\dfrac{1}{25}=\dfrac{1}{v}

\dfrac{1}{v}=-\dfrac{1421}{98025}

v=-68.98\ cm

The eye's near point is 68.98 cm from the eye.

(b). We need to calculate the focal length

Using formula of power

f =\dfrac{1}{P}

Put the value into the formula

f=-\dfrac{100}{3.00}

f=-33.33\ cm

We need to calculate the image distance

Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{-33.33}=\dfrac{1}{v}-\dfrac{1}{\infty}

-\dfrac{1}{33.33}+\dfrac{1}{\infty}=\dfrac{1}{v}

\dfrac{1}{v}=-\dfrac{1}{33.33}

v=-33.33\ cm

The eye's far point is 33.33 cm from the eye.

Hence, (a). The eye's near point is 68.98 cm from the eye.

(b). The eye's far point is 33.33 cm from the eye.

5 0
3 years ago
The density of aluminum is 2.70 g/ml. A piece of aluminum foil has a mass of 44 g. What is the volume of this piece of aluminum
anyanavicka [17]

Answer:

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Explanation:

Density is equal to the ratio between the mass of an object and its volume:

d=\frac{m}{V}

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In our problem, we know:

- density of aluminium: d=2.70 g/mL

- mass of the aluminium foil: m=44 g

So we can re-arrange the equation above and use these data to find the volume of the piece of aluminium foil:

V=\frac{m}{d}=\frac{44 g}{2.70 g/mL}=16.3 mL

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alina1380 [7]

Answer:

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The constant is the temperature of the air that the plants get.

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