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IrinaVladis [17]
3 years ago
12

What technique is used by all three branches of science to make discoveries

Physics
1 answer:
Margaret [11]3 years ago
5 0
BAH! Took me forever to think of it.

The Scientific method.

Brainliest please. :D
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How can the center of gravity of a rigid body be determined?
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To calculate the center of gravity, divide total weight distance moment by total mass of the system. Thus, the center of gravity is 13 meter from left-hand side.
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When was that last time you cried ? You can tell me
Inessa [10]

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honestly i cant remember now. i think when i was stressed about school and how it destroyed my summer schedule

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There is a 250-m-high cliff at half dome in yosemite national park in california. suppose a boulder breaks loose from the top of
lorasvet [3.4K]

Part A. For this part, we use two equations for linear motion:

<span>y = y0 + v0 t + 0.5 g t^2                   ---> 1</span>

<span>vf = v0 + g t                                         ---> 2</span>

First we solve for t using equation 1: y0 = 0 (initial point at top), y = 250 m, v0 = 0 (at rest)

250 = 0.5 (9.8) t^2

t = 7.143 s

Now we solve for final velocity vf using equation 2:

vf = g t

vf = 9.8 (7.143)

vf = 70 m/s

 

Part B. First we solve for the time it takes for the sound to reach the tourist.

t(sound) = 250 / 335 = 0.746 s

Therefore the total time would be:

t = 0.746 s + 0.300 s

t = 1.05 s

 

<span>Hence there is enough time for the tourist to get out before the boulder hits him.</span>

7 0
4 years ago
Read 2 more answers
A force of 125n is applied to a 50kg. Mass what is the assceleration of the mass
spayn [35]
F=ma
F=125 N
m= 50 kg
125=50a
a=2.5 m/s^2
3 0
3 years ago
¿Juan quiere calentar una barra de aluminio de 100 g, para realizar un trabajo. La temperatura ambiente es de 27°C pero necesita
Luda [366]

Answer:

<em>709.5 cal</em>

<em></em>

Explanation:

masa m de la barra de aluminio = 100 g

temperatura ambiente = 27 ° C

<em>Asumiremos que la barra de aluminio está en equilibrio térmico con el ambiente. </em>

Esto significa que la temperatura inicial de la barra es de 27 ° C

temperatura final a la que la barra debe calentarse = 60 ° C

el aumento de temperatura ΔT será

ΔT = 60 ° C - 27 ° C = 33 ° C

capacidad calorífica específica c del aluminio = 0.215 cal/g°C

Calor C requerido = mcΔT

<em>C = 100 x 0.215 x 33 = 709.5 cal</em>

8 0
3 years ago
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