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3 years ago

8. What is the momentum of a 120-kg professional fullback running across the line at 11.2 m/s?

Physics

1 answer:

Alchen [17]3 years ago

5 0

Answer:

134r kgm^-1 or 1344 kg /m

Explanation:

Momentum is is given by:

p=mv

Where:

p is momentum, m is mass in kg and v is velocity in ms−1

p=120kg×11.2 m/ s= 1344 kgms=1344kgm^−1

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Mystical ride her scooter down the hill from the state of rest when she reaches the bottom of the hill 4.0 seconds later her spe

mina [271]

The acceleration is $2.5 m/s^2$

Explanation:

This is a uniformly accelerated motion (constant acceleration), therefore we can apply the following suvat equation:

$v=u+at$

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

For the scooter in this problem, we have

u = 0 (it starts from rest)

v = 10.0 m/s is the final velocity

t = 4.0 s is the time interval

Solving for a, we find the acceleration:

$a=\frac{v-u}{t}=\frac{10-0}{4}=2.5 m/s^2$

Learn more about acceleration:

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3 years ago

A horizontal black line at left labeled A has a blue arrow pointing down to it and another blue arrow pointing down from it. A h

never [62]

Answer:

The Correct answer is B

7 0

3 years ago

Read 2 more answers

Why might measuring changes in speed or direction be important?

aliya0001 [1]

It’s important because if you were let’s say training to see how far you go in 10sec you need to record your data to see how much you are improving in that skill or something

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3 years ago

A capacitor is connected to an ac generator that has a frequency of 2.3 kHz and produces a rms voltage of 1.5 V. The rms current

miv72 [106K]

Answer:

Explanation:

Given that,

AC frequency of 2.3KHz

f=2.3×10³Hz

Vrms produce is

Vrms=1.5V

Current rms

Irms= 31mA

The capacitor is reconnected to a generator of frequency

f=4.8KHz =4800Hz

The current rms becomes

Irms= 85mA

Vrms=?

Solution

First genrator

The capacitive reactance is given as

Xc=Vrms/Irms

Xc=1.5/31×10^-3

Xc=48.39 ohms

Now, to know the capacitance of the capacitor

Xc=1/2πfC

Then,

C=1/2πfXc

So,

C=1/2×π×2300×48.39

C=1.43×10^-6C

C=1.43μF

Note: the capacitance of the capacitor did not change,

Now for generator two.

The reactance are given as

Xc=1/2πfC

Xc=1/2×π×4800×1.43×10^-6

Xc=23.19ohms

Then,

Vrms2=Irms2 ×Xc

Vrms2=85×10^-3×23.19ohms

Vrms2=1.97V

Vrms2=1.97Volts

7 0

3 years ago

a toy propeller fan with a moment of inertia of .034 kg x m^2 has a net torque of .11Nxm applied to it. what angular acceleratio

Harman [31]

Answer:

The angular acceleration is $\alpha = 3.235 \ rad/s ^2$

Explanation:

From the question we are told that

The moment of inertia is $I = 0.034\ kg \cdot m^2$

The net torque is $\tau = 0.11\ N \cdot m$

Generally the net torque is mathematically represented as

$\tau = I * \alpha$

Where $\alpha$ is the angular acceleration so

$\alpha = \frac{\tau }{I}$

substituting values

$\alpha = \frac{0.1 1}{ 0.034}$

$\alpha = 3.235 \ rad/s ^2$

6 0

3 years ago