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2 years ago

8. What is the momentum of a 120-kg professional fullback running across the line at 11.2 m/s?

Physics

1 answer:

Alchen [17]2 years ago

5 0

Answer:

134r kgm^-1 or 1344 kg /m

Explanation:

Momentum is is given by:

p=mv

Where:

p is momentum, m is mass in kg and v is velocity in ms−1

p=120kg×11.2 m/ s= 1344 kgms=1344kgm^−1

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A plane traveled west for 4.0 hours and covered a distance of 4,400 meters what’s the velocity

tatuchka [14]

0.31m/s

Explanation:

Given parameters:

Time of travel = 4hrs = 4 x 60 x 60 = 14400s

Displacement = 4400m due west

Unknown:

Velocity = ?

Solution:

Velocity is defined as the displacement per unit of time. It is expressed in m/s or km/hr:

Velocity = $\frac{displacement}{time}$

Velocity = $\frac{4400}{14400}$ = 0.31m/s

Learn more:

Velocity brainly.com/question/10883914

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3 years ago

What's the gravity?

poizon [28]

Answer:

gravity is the force by which a planet or another body draws objects towards its Centre. the force of gravity keeps all of the planets in an orbit around the sun.

Explanation:

what is gravity made of?

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2 years ago

An amusement park ride consists of a rotating circular platform 8.26 m in diameter from which 10 kg seats are suspended at the e

VashaNatasha [74]

To solve this problem we will begin by finding the necessary and effective distances that act as components of the centripetal and gravity Forces. Later using the same relationships we will find the speed of the body. The second part of the problem will use the equations previously found to find the tension.

PART A) We will begin by finding the two net distances.

$r = \frac{8.26}{2} = 4.13m$

And the distance 'd' is

$d = lsin\theta$

$d = 1.14 sin 16.2\°$

$d = 0.318m$

Through the free-body diagram the tension components are given by

$Tcos\theta = mg$

$Tsin\theta = \frac{mv^2}{R}$

Here we can watch that,

$R = r+d$

Dividing both expression we have that,

$tan\theta = \frac{v^2}{Rg}$

Replacing the values,

$tan(16.2) = \frac{v^2}{(4.13+0.318)(9.8)}$

$v = 4.83371m/s$

PART B) Using the vertical component we can find the tension,

$Tcos\theta = mg$

$T = \frac{mg}{cos\theta}$

$T = \frac{(10+26.2)(9.8)}{cos(16.2)}$

$T = 369.42N$

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3 years ago

Abdominal breathing is a condition in which only the inferior half of the lungs can be seen expanding and contracting with each

lilavasa [31]

Answer:

The correct answer is - Damage to the nerves that control the diaphragm.

Explanation:

Abdominal breathing is a condition in which inferior half of the lungs can be seen relaxing or contracting and expanding with the breath. This condition occurs due to the various conditions that lead to the respiratory.

It is cause due to the damage to nerves that control the diaphragm. The phrenic nerve is one of the nerve of diaphragm initiates in the neck and passes down.

Thus, the correct answer is - Damage to the nerves that control the diaphragm.

The phrenic nerve is a nerve that originates in the neck (C3–C5) and passes down between the lung and heart to reach the diaphragm.

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2 years ago

Help !!!!!!!!<br>Please its Urgent.<br>

Wewaii [24]

None can.

A clinical thermometer only measures temperatures above +30°C.

Mercury and alcohol are both frozen solid at -50°C.

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2 years ago