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2 years ago

During dehydration synthesis, a ________ molecule is produced.

1 answer:

6 0

*** Remember *** Dehydration synthesis is when two molecules are joined together, by removing a water molecule. Also a key thing to remember is that dehydration can be remembered as "losing water".

During dehydration synthesis, a  water  molecule is produced.

I hope this helps! :D

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WHEN I SAY I NEED HELP ASAP !!!

sweet [91]

Answer:

monoxide

dioxide

trioxide

tetroxide

pentoxide

hexoxide

heptoxide

octoxide

nonoxide

Explanation:

Just the way it is. If there is an -a or -o infront of the oxide(or another substance that starts with vowel), the a is often dropped.

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2 years ago

A football is inflated to 12psi at 20°C What is the new pressure in the football

Radda [10]

Answer: The new pressure is 3 psi.

Explanation:

Given: $P_{1}$ = 12 psi, $T_{1} = 20^{o}C$

$P_{2}$ = ?, $T_{2} = 5^{o}C$

Formula used is as follows.

$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{12 psi}{20^{o}C} = \frac{P_{2}}{5^{o}C}\\P_{2} = \frac{12 psi \times 5^{o}C}{20^{o}C}\\= 3 psi$

Thus, we can conclude that the new pressure is 3 psi.

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3 years ago

How would one convert 15 seconds to hours?

laiz [17]

Explanation:

a ...15 seconds×(3600 seconds hour)

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2 years ago

Read 2 more answers

How many half-lives are required for the concentration of reactant to decrease to 1.56% of its original value?4247.56.56

neonofarm [45]

Answer:

6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.

Explanation:

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Given:

Concentration is decreased to 1.56 % which means that 0.0156 of $[A_0]$ is decomposed. So,

$\frac {[A_t]}{[A_0]}$ = 0.0156

Thus,

$\frac {[A_t]}{[A_0]}=e^{-k\times t}$

$0.0156=e^{-k\times t}$

kt = 4.1604

The expression for the half life is:-

Half life = 15.0 hours

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac {ln\ 2}{t_{1/2}}$

$\frac{4.1604}{t}=\frac {ln\ 2}{t_{1/2}}$

$t = 6\times t_{1/2}$

6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.

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3 years ago

Explain how to use the displacement method to find the volume of an object?

DENIUS [597]

A submerged object displaces a volume of liquid equal to the volume of the object. One milliliter (1 mL) of water has a volume of 1 cubic centimeter (1cm3).

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2 years ago