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borishaifa [10]
3 years ago
7

I) Briefly discuss the strengths and weaknesses of the four spectroscopy techniques listed below. Include in your answer the spe

cific structural information you get from each method.
 IR
 UV-VIS
 NMR
 Mass Spec
Chemistry
1 answer:
klemol [59]3 years ago
4 0

delete please .....................................

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Particle with more energy move _________ than particles with less energy.
s2008m [1.1K]
Faster and farther apart
5 0
3 years ago
Read 2 more answers
How many moles of ammonium sulfate can be from the reaction of 30.0 mol of NH3 with H2SO4 according to the following equation: 2
marysya [2.9K]

Answer:

15 moles of  ammonium sulfate would be formed from 30 moles of ammonia.

Explanation:

Given data:

Number of moles of ammonium sulfate formed = ?

Number of moles of ammonia = 30.0 mol

Solution:

Chemical equation:

2NH₃  +   H₂SO₄  →  (NH₄)₂SO₄

Now we will compare the moles of ammonium sulfate with ammonia.

                           NH₃           :           (NH₄)₂SO₄

                             2              :               1

                            30.0          :              1/2×30.0 = 15.0 mol

So 15 moles of  ammonium sulfate would be formed from 30 moles of ammonia.

7 0
3 years ago
How many molecules are in 3 moles of potassium bromide (KBr)
sattari [20]

Answer:

Your strategy here will be to use the molar mass of potassium bromide,

KBr

, as a conversion factor to help you find the mass of three moles of this compound.

So, a compound's molar mass essentially tells you the mass of one mole of said compound. Now, let's assume that you only have a periodic table to work with here.

Potassium bromide is an ionic compound that is made up of potassium cations,

K

+

, and bromide anions,

Br

−

. Essentially, one formula unit of potassium bromide contains a potassium atom and a bromine atom.

Use the periodic table to find the molar masses of these two elements. You will find

For K:

M

M

=

39.0963 g mol

−

1

For Br:

M

M

=

79.904 g mol

−

1

To get the molar mass of one formula unit of potassium bromide, add the molar masses of the two elements

M

M KBr

=

39.0963 g mol

−

1

+

79.904 g mol

−

1

≈

119 g mol

−

So, if one mole of potassium bromide has a mas of

119 g

m it follows that three moles will have a mass of

3

moles KBr

⋅

molar mass of KBr



119 g

1

mole KBr

=

357 g

You should round this off to one sig fig, since that is how many sig figs you have for the number of moles of potassium bromide, but I'll leave it rounded to two sig figs

mass of 3 moles of KBr

=

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

360 g

a

a

∣

∣

−−−−−−−−−

Explanation:

<em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em>:</em><em> </em><em>3</em><em>6</em><em>0</em><em> </em><em>g</em><em> </em>

6 0
3 years ago
(My losing emote at the top..)
forsale [732]

Answer:

neutral charge

I hope it's helps you

4 0
3 years ago
Read 2 more answers
A compound has a percent composition of 15.24% sodium (molar mass = 22.99
RUDIKE [14]

The empirical formula of the compound obtained from the question given is NaBrO₃

<h3>Data obtained from the question </h3>
  • Sodium (Na) = 15.24%
  • Bromine (Br) = 52.95%
  • Oxygen (O) = 31.81%
  • Empirical formula =?

<h3>How to determine the empirical formula </h3>

The empirical formula of the compound can be obtained as illustrated below:

Divide by their molar mass

Na = 15.24 / 22.99 = 0.663

Br = 52.95 / 79.90 = 0.663

O = 31.81 / 16 = 1.988

Divide by the smallest

Na = 0.663 / 0.663 = 1

Br = 0.663 / 0.663 = 1

O = 1.988 / 0.663 = 3

Thus, the empirical formula of the compound is NaBrO₃

Learn more about empirical formula:

brainly.com/question/24297883

8 0
2 years ago
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