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borishaifa [10]
3 years ago
7

I) Briefly discuss the strengths and weaknesses of the four spectroscopy techniques listed below. Include in your answer the spe

cific structural information you get from each method.
 IR
 UV-VIS
 NMR
 Mass Spec
Chemistry
1 answer:
klemol [59]3 years ago
4 0

delete please .....................................

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A compound is found to have an empirical formula of CH2O. If its molecular mass is 60.0 g/mol, what is its molecular formula?
Lina20 [59]
Empirical=12.01+2.02+16=30.03
Molecular=60
Molecular/Empirical=2
so, 2(CH2O)
C2H4O2
3 0
3 years ago
A 50 mL beaker has an uncertainty of ± 10%. What is the absolute uncertainty for this beaker?
Pani-rosa [81]

Answer:

The absolute uncertainty is 10%.

Explanation:

The absolute uncertainty, sometimes referred to as absolute error, is the size of the possible range of values where by the actual or true value of a measurement probably lies.

The uncertainty of the 50 mL beaker is given as  ± 10%. This implies that the volume recorded using the beaker will either be 10 % above or below the actual volume.

The absolute uncertainty ignores the direction of the error, whether above or below, and is mostly concerned with the magnitude of the error. We simply ignore the signs of the uncertainty and this will give the value of the absolute uncertainty.

5 0
3 years ago
Read 2 more answers
The observed rotation of 2.0 gg of a compound in 50 mLmL of solution in a polarimeter tube 25-cmcm long is +47.2 ∘∘ . What is th
Anastaziya [24]

Answer:

[∝] = +472

Explanation:

Specific rotation in a solution is defined as:

[∝] = ∝ / c×l

Where:

[∝] is specific rotation, ∝ is observed rotation (In degrees), c is concentration in g/mL and l is path length (In dm).

∝: +47.2°

c: 2.0g / 50mL = 0.04g/mL

l: 25cm × (1dm /10cm) = 2.5dm

Replacing:

[∝] = +47.2° / 0.04g/mL×2.5dm = <em>+472</em>

I hope it helps!

4 0
3 years ago
Which represents the empirical formula for a3B9
Viktor [21]
A3B9 represents a molecular formula. The representation of the empirical formula for this compound is AB3. This is so because the empirical formula is the simplest ratio of the atoms present in the molecule. You get AB3 when you divide the subscripts of A3B9, this is 3 and 9, by the greatest common factor, which is 3. 3/3 = 1 and 9/3 = 3, so the subscripts for the empirical formula are 1 and 3, which is what AB3 represents. <span>Answer: AB3.</span>
3 0
3 years ago
List the properties of copper, sulfur and copper sulfide?
Y_Kistochka [10]
The answer would be metal
7 0
3 years ago
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