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2 years ago

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Object A attracts object B with a gravitational force of 5 newtons from a given distance. If the distance between the two object

s is reduced in
half, what will be the changed force of attraction between them?
A. 2.5 newtons
B. 10 newtons
C.15 newtons
D. 20 newtons
E. 25 newtons

1 answer:

alukav5142 [94]2 years ago

3 0

The new force of gravitational attraction is D. 20 newtons

Explanation:

The magnitude of the gravitational force between two objects is given by :

$F=G\frac{m_1 m_2}{r^2}$ (1)

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}$ is the gravitational constant

m1, m2 are the masses of the two objects

r is the distance between them

In this problem, the initial gravitational force between the two objects A and B is

F = 5 N

When the distance between them is r.

Later, the distance is reduced in half:

$r' = \frac{r}{2}$

Substituting into eq.(1), we see how does the force change:

$F' = G\frac{m_1 m_2}{r'^2}=G\frac{m_1 m_2}{(r/2)^2}= 4 (G\frac{m_1 m_2}{r^2})=4F$

So, the force increases by 4 times. Therefore, the new force is

$F'=4F=4(5 N) = 20 N$

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

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