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valkas [14]
3 years ago
12

A man stands still on a moving walkway that is going at a speed of 0.3 m/s to the south. What is the velocity of the man accordi

ng to a stationary observer?
Physics
2 answers:
allochka39001 [22]3 years ago
6 0

Answer:

With respect to stationary observer the velocity of man is 0.3 m/s towards South

Explanation:

As we know that here man is standing still on the moving walkway

so here we can say that velocity of man with respect to walkway is zero

\vec v_{mw} = 0

now as per relative velocity concept we know

\vec v_{mw} = \vec v_m - \vec v_w

here we know

\vec v_m = velocity of man with respect to stationary observer

\vec v_w = velocity of walkway

now from above equation we have

\vec v_m = \vec v_{mw} + \vec v_w

now plug in all values in it

\vec v_m = 0 + 0.3 m/s = 0.3 m/s towards South

RSB [31]3 years ago
3 0
The velocity is 0.3 m/s South.
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Answer:

The angle between the mirrors is 90°.

Explanation:

Given that,

Number of image = 5

Rahul kept two plane mirrors at a certain angle in front of a burning candle.

We need to find the angle between the mirrors

Using given data

When Rahul kept two plane mirrors at a certain angle in front of a burning candle then see the 5 image of candle in the mirrors.

If rahul kept two plane mirrors at a 90° then we get the 5 image of candle.

Firstly we see the two images in both mirror and now first image of first mirror is see in second mirror and second image of second mirror is see in first mirror.

So, we can say that we see the 5 image of candle in the mirrors.

Hence, The angle between the mirrors is 90°.

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3 years ago
How can you increase the rate of a reaction? Select all that apply. *
sergij07 [2.7K]

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6 0
3 years ago
A 10kg object experiences a horizontal force which causes it to accelerate 5 m/s2 moving it a distance of 20 m horizontally. How
mr_godi [17]

Answer:

The work done by the force is 1000 J.

Explanation:

Given:

Mass of object (m) = 10 kg

Acceleration of the object (a) = 5 m/s²

Displacement of the object (S) = 20 m

Using Newton's second law, we have:

Force = Mass × Acceleration

F=ma

Plug in the given values and solve for force 'F' acting on the object. This gives,

F=(10\ kg)(5\ m/s^2)\\\\F=50\ N

Now, work done by the force 'F' is equal to the product of force 'F' and the displacement it cause in its direction which is 20 m.

Therefore, the work done by the force is given as:

Work = Force × Displacement

W=FS

Plug in the values given and solve for 'W'. This gives,

W=50\ N\times 20\ m \\\\W=1000\ J

Therefore, the work done by the force is 1000 J.

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4 years ago
The value of the normal force exerted on a 2,000 gram block on a table
kobusy [5.1K]

Answer:

N = 19.6 N

Explanation:

Given that,

Mass of a block, m = 2000 g

1 kg = 1000 g

It means, 2000 g = 2kg

We need to find the value of normal force on the block on a table. Normal force is balanced by the weight of the block as follows :

N = mg, g is acceleration due to gravity

N = 2 kg × 9.8 m/s²

N = 19.6 N

So, the normal force acting on the block is 19.6 N.

4 0
3 years ago
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