Answer:
put these numbers in the boxes from up to down. hope this helps! :)
Explanation:
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Answer:
dimensions of k are kg / s^2
Explanation:
F=ma (Newton's second law)
F=-kx (Hooke's law)
so equate both
-kx = ma
k = -ma/x
= mass * acceleration / distance (dimensions, -1 has no dimension)
= kg * m/s^2 / m
= kg / s^2
Answer:
W_net = μ 5.58, μ = 0.1 W_net = 0.558 J
Explanation:
The work is defined by the related
W = F. d = F d cos θ
where bold indicates vectors.
In the case, the work of the friction force on a circular surface is requested.
The expression for the friction force is
fr = μ N
the friction force opposes the movement, therefore the angle is 180º and the cos 180 = -1
W = - fr d
the path traveled half the length of the circle
L = 2 π R
d = L / 2
d = π R
we substitute
W = - μ N d
Total work is initial to
W_neto = - μ π R (N_b - N_a)
let's calculate
W_net = - μ π 0.550 (0.670 - 3.90)
W_net = μ 5.58
for the complete calculation it is necessary to know the friction coefficient, if we assume that μ = 0.1
W_net = 0.1 5.58
W_net = 0.558 J
This question involves the concepts of Newton's Law of Gravitation and mass.
The force on Procyon A from Procyon B will be "equal" to the force on Procyon B from Procyon A, which has a value of "3.75 x 10²⁶ N".
Applying Newton's Law of Gravitation, we can find the force on Procyon A from Procyon B, which is equal to the force on Procyon B from Procyon A:

where,
F = force = ?
G = universal gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg²
m₁ = mass of Procyon A = 3 x 10³⁰ kg
m₂ = mass of Procyon B = (2.5)(3 x 10³⁰ kg) = 7.5 x 10³⁰ kg
r = distance between them = 2 x 10¹² m
Therefore,

<u>F = 3.75 x 10²⁶ N</u>
Learn more about Newton's Law of Gravitation here:
brainly.com/question/17931361?referrer=searchResults
A I think .......
Explanation: