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valkas [14]
3 years ago
12

A man stands still on a moving walkway that is going at a speed of 0.3 m/s to the south. What is the velocity of the man accordi

ng to a stationary observer?
Physics
2 answers:
allochka39001 [22]3 years ago
6 0

Answer:

With respect to stationary observer the velocity of man is 0.3 m/s towards South

Explanation:

As we know that here man is standing still on the moving walkway

so here we can say that velocity of man with respect to walkway is zero

\vec v_{mw} = 0

now as per relative velocity concept we know

\vec v_{mw} = \vec v_m - \vec v_w

here we know

\vec v_m = velocity of man with respect to stationary observer

\vec v_w = velocity of walkway

now from above equation we have

\vec v_m = \vec v_{mw} + \vec v_w

now plug in all values in it

\vec v_m = 0 + 0.3 m/s = 0.3 m/s towards South

RSB [31]3 years ago
3 0
The velocity is 0.3 m/s South.
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It's just asking you to sit down and COUNT the little squares in each sector.

It'll help you keep everything straight if you take a very sharp pencil and make a tiny dot in each square as you count it.  That way, you'll be able to see which ones you haven't counted yet, and also you won't count a square twice when you see that it already has a dot in it.

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