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Virty [35]
2 years ago
12

Can anyone help me with this problem? It is -2.1??

Physics
1 answer:
nata0808 [166]2 years ago
8 0
Question not clear or read-able
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After a marathon many runners are given a shiny, aluminium blanket to wrap around their bodies. Explain why the blanket is shiny
vodomira [7]
So then they get warmed up and can be seen easily

3 0
2 years ago
Which best describes a characteristic of an adiabatic process?
neonofarm [45]

Answer:

<h3>Can you please provide the choices? For now this is all I can give you.</h3>

Explanation:

In thermodynamics, an adiabatic process is a type of thermodynamic process which occurs without transferring heat or mass between the system and its surroundings.Unlike an isothermal process, an adiabatic process transfers energy to the surroundings only as work. It also conceptually supports the theory used to explain the first law of thermodynamics and is therefore a key thermodynamic concept.

5 0
3 years ago
Read 2 more answers
A) explain how the data matches each line on the graph (give name and line letter for each)
stepladder [879]
The answer you have is right good job 12
3 0
2 years ago
The phenomenon of vehicle "tripping" is investigated here. The sport-utility vehicle is sliding sideways with speed v1 and no an
Mrrafil [7]

Answer:

v_1  = 3.5 \ m/s

Explanation:

Given that :

mass of the SUV is  = 2140 kg

moment of inertia about G , i.e I_G = 875 kg.m²

We know from the conservation of angular momentum that:

H_1= H_2

mv_1 *0.765 = [I+m(0.765^2+0.895^2)] \omega_2

2140v_1*0.765 = [875+2140(0.765^2+0.895^2)] \omega_2

1637.1 v_1 = 3841.575 \omega_2

\omega_2 = \frac{1637.1 v_1}{3841.575}

\omega _2 = 0.4626 \ v_1

From the conservation of energy as well;we have :

T_2 +V_{2  \to 3} = T_3 \\ \\ \\  \frac{1}{2} I_A \omega_2^2 - mgh =0

[\frac{1}{2} [875+2140(0.765^2+0.895^2)](0.4262 \ v_1)^2 -2140(9.81)[\sqrt{0.76^2+0.895^2} -0.765]] =0

706.93 \ v_1^2 - 8657.49 =0

706.93 \ v_1^2  = 8657.49

v_1^2  =  \frac{8657.49}{706.93 }

v_1 ^2 =  12.25

v_1  = \sqrt{ 12.25

v_1  = 3.5 \ m/s

6 0
3 years ago
A 50 kg person receives an absorbed dose of gamma radiation of 20 millirads. What is the total energy absorbed?.
Masteriza [31]

For a 50 kg person receives an absorbed dose of gamma radiation of 20 millirads,  the total energy absorbed is mathematically given as

E=0.1457J

<h3>What is the total energy absorbed?</h3>

Generally, the equation for the total energy absorbed  is mathematically given as

E=mass*gamma radiation

Therefore

E=50*20*19^{-3}

E=0.1457J

In conclusion,  the total energy absorbed

E=0.1457J

Read more about Energy

brainly.com/question/13439286

4 0
1 year ago
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