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3 years ago

The process by which metamorphic rock changes to igneous rock begins with?

Physics

1 answer:

Strike441 [17]3 years ago

5 0

Melting, as igneous rock is magma or lava that has cooled and hardened.

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Jasmine is diving off a 3-meter springboard. her height in meters above the water when she is x meters horizontally from the end

olganol [36]

Answer:

5.25 m

Explanation:

Given;

The height equation h;

h=-x^2+3x+3

Where;

h = the height above water

x = horizontal distance from the end of the board

The maximum height is at h' = 0, when change in h with respect to change in x is equal to zero.

differentiating the equation h.

dh/dx = h' = -2x + 3 = 0

Solving for x;

2x = 3

x = 3/2

Substituting into the function h;

h max = -x^2+3x+3

h max = -(3/2)^2 + 3(3/2) +3 = -9/4 +9/2 +3 = 9/4 + 3 =

h max = 21/4 = 5.25 m

8 0

3 years ago

Pls help A car starts from rest and gains a velocity of 20m/s in 10 seconds calculate its acceleration and the distance covered

Soloha48 [4]

Answer:

$\boxed{\sf Acceleration \ (a) = 2 \ m/s^{2}}$

$\boxed{\sf Distance \ covered \ (s) = 100 \ m}$

Given:

Initial velocity (u) = 0 m/s

Final velocity (v) = 20 m/s

Time taken (t) = 10 sec

To Find:

(i) Acceleration (a)

(ii) Distance covered (s)

Explanation:

$\sf (i) \ From \ 1^{st} \ equation \ of \ motion:$

$\sf \implies v = u + at$

$\sf \implies 20 = 0 + a(10)$

$\sf \implies 10a = 20$

$\sf \implies \frac{10a}{10} = \frac{20}{10}$

$\sf \implies a = 2 \: m/ {s}^{2}$

$\sf (ii) \ From \ 2^{nd} \ equation \ of \ motion:$

$\sf \implies s = ut + \frac{1}{2} a {t}^{2}$

$\sf \implies s = (0)(10) + \frac{1}{2} \times 2 \times {(10)}^{2}$

$\sf \implies s = \frac{1}{ \cancel{2}} \times \cancel{2} \times {(10)}^{2}$

$\sf \implies s = {10}^{2}$

$\sf \implies s = 100 \: m$

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3 years ago

The four principle surveying methods to spatially determine the position of features are: Select one: ut of a. triangulation, tr

Natalija [7]

A: perpendicular offset

B: radiation

C: transliteration

D: theodolite

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3 years ago

A small rubber ball is thrown at a heavier, larger basketball that is still. The small ball bounces off the basketball. Assume t

meriva

Part A.
The forces are the same because the force from the smaller ball it transferring its Energy through the basketball and it's rebounding as Connecticut Energy back up to the smaller ball

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3 years ago

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If you can answer my last post ill give you 75 points pls its very important and please make sure it correct!!!!!!!

Hoochie [10]

Answer:

I can't see the post :/

Explanation:

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2 years ago

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