Eight joules of work is required to stretch a spring 0.5 meter from its natural length. Find the work required to stretch the sp
1 answer:
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That's true.
Netwon's second law states that the resultant of the forces F acting on a body is equal to the product between its mass m and its acceleration a:
This means that if the net force acting on an object is different from zero (term on the left), than the acceleration of the object (term on the right) must be different from zero as well, and therefore the body is accelerating.
In particular, both F and a in the equation are vectors: this means that if the acceleration is positive, F and a have the same direction. In this problem, the acceleration is positive (because the object is speeding up), therefore the force and the acceleration have same direction.
Netwon's second law states that the resultant of the forces F acting on a body is equal to the product between its mass m and its acceleration a:
This means that if the net force acting on an object is different from zero (term on the left), than the acceleration of the object (term on the right) must be different from zero as well, and therefore the body is accelerating.
In particular, both F and a in the equation are vectors: this means that if the acceleration is positive, F and a have the same direction. In this problem, the acceleration is positive (because the object is speeding up), therefore the force and the acceleration have same direction.
Answer:
q2 = 9.02*10^{-4}C
Explanation:
To find the value of the other charge you use the Coulomb's law:
k: Coulomb's constant = 8.98*10^{9}Nm^2/C^2
q1: charge 1 = 55*10^{-6}C
r: distance between charges = 90cm = 0.9m
F: electric force = 550N
By doing q2 the subject of the formula and replacing you obtain:
hence, the value of the other charge q2 is 9.02*10^{-4}C