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Amiraneli [1.4K]
3 years ago
8

How did early photosynthetic organisms change Earth’s atmosphere?

Physics
1 answer:
irga5000 [103]3 years ago
6 0
<span>They tremove CO2 from the atmosphere and release O2 as a waste product.
hope this helped :)</span>
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A cyclist is riding his bike up a mountain trail. When he starts up the trail, he is going 8 m/s. As the trail gets steeper, he
shusha [124]

Answer:

a)   a = - 0.0833 m / s²,  b)   t = 4.4 s

Explanation:

a) this is a kinematics exercise where the acceleration is along the inclined plane

         v = v₀ - a t

         a = v₀ - v / t

         a = 3 - 8/60

         a = - 0.0833 m / s²

b) in this case the final velocity is zero

         v = v₀ - a t

         0 = v₀ - at

         t = v₀ / a

         t = 28 / 6.4

         t = 4.375 s

         t = 4.4 s

3 0
3 years ago
Which instrument is used to measure depth of ocean ?
skelet666 [1.2K]
Echo sounding is a type of SONAR used to determine the depth of water by transmitting sound pulses into water. The time interval between emission and return of a pulse is recorded, which is used to determine the depth of water along with the speed of sound in water at the time.
5 0
3 years ago
Flint glass materials ​
Kipish [7]

Answer:

Flint glass is combination of silicon dioxide (SiO2) with lead or potassium. It creates a relatively high refractive index and high degree of light dispersing power compared to other types of glass.

Explanation:

:)

7 0
3 years ago
Read 2 more answers
Which process produces the energy radiated by the star when it becomes a main sequence star?
inysia [295]
The process that produces the energy radiated by stars is nuclear fusion in the core.
For a star on the main sequence, it's the fusion of hydrogen nuclei into helium.
8 0
4 years ago
For a wire has a circular cross section with a radius of 1.23mm.
Mila [183]

Answer:

5.731\times 10^{-5}\ m/s

Decrease

Explanation:

I = Current = 3.7 A

e = Charge of electron = 1.6\times 10^{-19}\ C

n = Conduction electron density in copper = 8.49\times 10^{28}\ electrons/m^3

v_d = Drift velocity of electrons

r = Radius = 1.23 mm

Current is given by

I=neAv_d\\\Rightarrow v_d=\dfrac{I}{neA}\\\Rightarrow v_d=\dfrac{3.7}{8.49\times 10^{28}\times 1.6\times 10^{-19}\times \pi (1.23\times 10^{-3})^2}\\\Rightarrow v_d=5.731\times 10^{-5}\ m/s

The drift speed of the electrons is 5.731\times 10^{-5}\ m/s

v_d=\dfrac{I}{neA}

From the equation we can see the following

v_d\propto \dfrac{1}{n}

So, if the number of conduction electrons per atom is higher than that of copper the drift velocity will decrease.

5 0
3 years ago
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