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11Alexandr11 [23.1K]
3 years ago
8

Does a front always mean one air mass will be displaced by another? When is there no displacement?

Physics
1 answer:
tangare [24]3 years ago
4 0

Answer:

Not necessarily, if the air masses are not strong enough, a stationary front is caused

Explanation:

A front is a block of separation between two air masses at different temperatures. They can be classified as cold, warm, stationary and occluded fronts. When a front is formed, a collision occurs between the two masses, generating a very dynamic activity, with electrical storms, gusts of wind and downpours.

A stationary front is one where neither of the two air masses are strong enough to replace the other. On such a front can generate atmospheric conditions such as prolonged rainfall and high cloudiness.

After several days, the stationary fronts may dissipate or become a cold or warm front. .

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A star produces 2x10^26 watts. how much energy does it lose every minutes
Step2247 [10]

Answer:

Energy loss per minute will be 120\times 10^{26}j

Explanation:

We have given the star produces power of 2\times 10^{26}W

We know that 1 W = 1 J/sec

So 2\times 10^{26}W=2\times 10^{26}J/sec

Given time = 1 minute = 60 sec

So the energy loss per minute =2\times 10^{26}\times 60=120\times 10^{26}j

We multiply with 60 we have to calculate energy loss per minute

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3 years ago
What are non examples of light years?
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In what scientific study did scientists discover that when atoms split they _________.
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Explanation:

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3 years ago
If a farsighted person has a near point that is 0.600 mm from the eye, what is the focal length f2f2f_2 of the contact lenses th
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Answer:

0.22mm

Explanation:

A far sighted person is a person suffering from long sightedness i.e such individual can only see far distant object clearly but not near distant object. The defect is corrected using convex lens.

Since convex lens is used, the focal (f) length of the lens is positive and the image distance (v) is also positive.

Using the lens formula,

1/f = 1/u + 1/v

Where u is the object distance = 0.35mm

v = 0.6mm

1/f = 1/0.35+1/0.6

1/f = 2.86 + 1.67

1/f = 4.53

f = 1/4.53

f = 0.22mm

The focal length of the contact lenses will be 0.22mm

5 0
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An object with a mass of 6.0 kg accelerates 8.0 m/s^2 when an unknown force is applied to it. What is the amount of the force? R
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Answer:

48N

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use F=ma, or force is equal to mass multiplied by acceleration.

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