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allsm [11]
4 years ago
15

A car travels 45 km due north and 70 km west. What is the car's displacement? 6 points 24.7 km northeast 83.2 km northwest 76.5

km northwest 115 km north
Physics
1 answer:
HACTEHA [7]4 years ago
8 0

Answer:

3150

Explanation:

if if you were two times 45 times 70 it would give you that answer

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A musician decides to make a digital recording of their concert so that they can share it with fans that cannot attend the conce
UNO [17]
In the digital recording process, the wave is measured or sampled, and the information is converted to mathematical units or quantized. ... The more often the wave is sampled (its sampling rate), the more fully the wave is reproduced. sampling rate. Number of digital samples taken per second.
6 0
3 years ago
An electric fan has the power output of 60W. How much work is done if the fan operates for 120s?
Digiron [165]
Since power = work done/time, 60= work done/120, work done = 120*60 = 7200. So,work done = 7200N (Newton). 
I'm not sure if you're supposed to convert the seconds to time.
4 0
4 years ago
What is primary succession? Give an example.
morpeh [17]

Answer:

primary succession is something that was t there before like a forest it once wasn’t there

Explanation:

7 0
4 years ago
(a) What is the ionization energy of a hydrogen atom that is in the n = 6 excited state? (b) For a hydrogen atom, determine the
crimeas [40]

Answer:

(a) 0.3778 eV

(b) Ratio = 0.0278

Explanation:

The Bohr's formula for the calculation of the energy of the electron in nth orbit is:

E=\frac {-13.6}{n^2}\ eV

(a) The energy of the electron in n= 6 excited state is:

E=\frac {-13.6}{6^2}\ eV

E=-0.3778\ eV

Ionisation energy is the amount of this energy required to remove the electron. Thus, |E| = 0.3778 eV

(b) For first orbit energy is:

E=\frac {-13.6}{1^2}\ eV

E=-13.6\ eV

Ratio=\frac {E_6}{E_1}

Ratio=\frac {-0.3778}{-13.6}

Ratio = 0.0278

7 0
4 years ago
Texting and driving is a dangerous act
sveta [45]

Answer:

s = 92.36 m

Explanation:

The distance covered by an object moving with uniform speed is given by the following formula:

s = vt

where,

s = distance covered by car during the time when driver was distracted in texting = ?

v = uniform speed of car = (95 km/h)(1 h/3600 s)(1000 m/1 km) = 26.39 m/s

t = time taken by the driver for texting = 3.5 s

Therefore, using these values in equation, we get:

s = (26.39 m/s)(3.5 s)

<u>s = 92.36 m</u>

4 0
4 years ago
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