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4 years ago

Please answer ASAP

Physics

1 answer:

garri49 [273]4 years ago

4 0

Perpendicular is the answer.

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What are two factors that determine object's gravitational potential energy? an

Artyom0805 [142]

Answer:

The factors that affect an object's gravitational potential energy are its height relative to some reference point, its mass, and the strength of the gravitational field it is in.

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2 years ago

Which is a chemical property that can be used to identify calcium carbonate?

Zina [86]

I think the answer is d i think

5 0

3 years ago

A mother is helping her children, of unequal weight, to balance on a seesaw so that they will be able to make it tilt back and f

horsena [70]

Answer:

L₁ = W×L / w

Explanation:

The scenario is shown in the image below.

At the pivot point, the torque acting on this point must be zero so that there will be easy back and forth without the heavier child.

Torque created by lighter child + Torque created by the heavier child = 0

Thus,

According to the axis system, the heavier child is left to the pivot (origin), so,

W×(- L ) + w× L₁ = 0

So,

L₁ = W×L / w

7 0

4 years ago

A drag racing car with a weight of 1600 lbf attains a speed of 270 mph in a quarter-mile race. Immediately after passing the tim

Kaylis [27]

Answer:

15.065ft

Explanation:

To solve this problem it is necessary to consider the aerodynamic concepts related to the Drag Force.

By definition the drag force is expressed as:

$F_D = -\frac{1}{2}\rho V^2 C_d A$

Where

$\rho$ is the density of the flow

V = Velocity

$C_d$ = Drag coefficient

A = Area

For a Car is defined the drag coefficient as 0.3, while the density of air in normal conditions is 1.21kg/m^3

For second Newton's Law the Force is also defined as,

$F=ma=m\frac{dV}{dt}$

Equating both equations we have:

$m\frac{dV}{dt}=-\frac{1}{2}\rho V^2 C_d A$

$m(dV)=-\frac{1}{2}\rho C_d A (dt)$

$\frac{1}{V^2 }(dV)=-\frac{1}{2m}\rho C_d A (dt)$

Integrating

$\int \frac{1}{V^2 }(dV)= - \int\frac{1}{2m}\rho C_d A (dt)$

$-\frac{1}{V}\big|^{V_f}_{V_i}=\frac{1}{2m}(\rho)C_d (\pi r^2) \Delta t$

Here,

$V_f = 60mph = 26.82m/s$

$V_i = 120.7m/s$

$m= 1600lbf = 725.747Kg$

$\rho = 1.21 kg/m^3$

$C_d = 0.3$

$\Delta t=7s$

Replacing:

$\frac{-1}{26.82}+\frac{1}{120.7} = \frac{1}{2(725.747)}(1.21)(0.3)(\pi r^2) (7)$

$-0.029 = -5.4997r^2$

$r = 2.2963m$

$d= r*2 = 4.592m \approx 15.065ft$

4 0

4 years ago

Why do cars stay in motion.

liubo4ka [24]

Answer:

Friction is the resistance to motion created by two objects moving against each other. Friction creates heat. Unless acted on by a force, objects in motion tend to stay in motion and objects at rest remain at rest.

6 0

3 years ago

Read 2 more answers