Answer:
1526.0 cubic units
Step-by-step explanation:
Rotating rectangle AKLM you will get cylinder with height KA and base radius KL. From the given data
![KA=\sqrt{(6-0)^2+(0-0)^2}=6,\\ \\KL=\sqrt{(0-0)^2+(9-0)^2}=9.](https://tex.z-dn.net/?f=KA%3D%5Csqrt%7B%286-0%29%5E2%2B%280-0%29%5E2%7D%3D6%2C%5C%5C%20%5C%5CKL%3D%5Csqrt%7B%280-0%29%5E2%2B%289-0%29%5E2%7D%3D9.)
The volume of the cylinder is
![V_{cylinder}=\pi r^2\cdot H.](https://tex.z-dn.net/?f=V_%7Bcylinder%7D%3D%5Cpi%20r%5E2%5Ccdot%20H.)
Then
![V_{cylinder}=\pi \cdot 9^2\cdot 6=486\pi \approx 1526.0\ un^3.](https://tex.z-dn.net/?f=V_%7Bcylinder%7D%3D%5Cpi%20%5Ccdot%209%5E2%5Ccdot%206%3D486%5Cpi%20%5Capprox%201526.0%5C%20un%5E3.)
the anwser is 24/625 is the anwser
Answer:
<u>-</u><u>5</u><u>g</u><u>(</u><u>4</u><u>)</u><u> </u><u>-</u><u> </u><u>1</u><u> </u><u>is</u><u> </u><u>9</u>
Step-by-step explanation:
![g(x) = 1 - \frac{3}{4} x](https://tex.z-dn.net/?f=g%28x%29%20%3D%201%20-%20%20%5Cfrac%7B3%7D%7B4%7D%20x)
when x is 4:
![g(4) = 1 - \frac{3}{4} \times 4 \\ = 1 - 3 \\ = - 2](https://tex.z-dn.net/?f=g%284%29%20%3D%201%20-%20%20%5Cfrac%7B3%7D%7B4%7D%20%20%5Ctimes%204%20%5C%5C%20%20%3D%201%20-%203%20%5C%5C%20%20%3D%20%20-%202)
therefore:
![- 5g(4) - 1 = - 5( - 2) - 1 \\ = 10 - 1 \\ = 9](https://tex.z-dn.net/?f=%20-%205g%284%29%20-%201%20%3D%20%20-%205%28%20-%202%29%20-%201%20%5C%5C%20%20%3D%2010%20-%201%20%5C%5C%20%20%3D%209)
Answer:(-5,-7)
Step-by-step explanation:
Rewrite in Vertex form and use this form to find the vertex (h,k)
Answer:
The answer is 14
Step-by-step explanation:
14x2=28
14x3=42 so the greatest common factor is 14