Answer:
D. 10 T
Explanation:
When a particle is moving in a magnetic field, the magnetic force provides the centripetal force that keeps the particle in circular motion.
The cyclotron period (the period the particle takes to complete one orbit) can be found to be
where
m is the mass of the particle
q is its charge
B is the magnetic field
As we see, the period is directly proportional to the mass of the particle.
In this problem, the second particle is ten times as massive as the first one:
m' = 10 m
while the speed is the same. So, the period of the second particle is
"he force exerted by the car is more than the force exerted b y the snowball" is the one among the following that can be said <span>about the magnitude of the forces exerted by the snowball and the car. The correct option among all the options that are given in the question is the first option or option "A". I hope it helps you.</span>
Answer:
a) W = 6.75 J and b) v = 3.87 m / s
Explanation:
a) In the problem the force is nonlinear and they ask us for work, so we must use it's definition
W = ∫ F. dx
Bold indicates vectors. In a spring the force is applied in the direction of movement, whereby the scalar product is reduced to the ordinary product
W = ∫ F dx
We replace and integrate
W = ∫ (-60 x - 18 x²) dx
W = -60 x²/2 -18 x³/3
Let's evaluate between the integration limits, lower W = 0 for x = -0.50 m, to the upper limit W = W for x = 0 m
W = -30 [0- (-0.50) 2] -6 [0 - (- 0.50) 3]
W = 7.5 - 0.75
W = 6.75 J
b) Work is equal to the variation of kinetic energy
W = ΔK
W = ΔK = ½ m v² -0
v =√ 2W/m
v = √(2 6.75/ 0.90)
v = 3.87 m / s
Answer:
There is no atmspheric pressure
"Frequency" just means "often-ness" ... how often something happens.
It's always expressed as
<em>(number of happenings) / (some period of time) .</em>
