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klemol [59]
3 years ago
14

If you weigh 690n on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and

a diameter of 19.0 km ?]
Physics
1 answer:
NeTakaya3 years ago
5 0
-- If you weigh 690N on the Earth, then your mass is about

           (690N) / (9.8 m/s²) = 70 kg .

-- If your mass is 70 kg then your weight on that neutron star would be

              G  M₁  M₂  /  R²

         =  (6.67 x 10⁻¹¹ N m²/kg²) (70 kg) (1.989 x 10³⁰ kg) / (19,000 m)²

         =  (6.67 x 10⁻¹¹ x 70 x 1.989 x 10³⁰) / (3.61 x 10⁸)        N

         =  (6.67 x 70 x 1.989 x 10¹⁹)  /  (3.61 x 10⁸)          N

         =    2.57 x 10¹³    Newtons .

  (about  2,890,000,000 tons !)
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A child whose weight is 287 N slides down a 7.20 m playground slide that makes an angle of 31.0° with the horizontal. The coeff
natulia [17]

Answer:

a

H  =212.6 \  J

b

v  =  7.647  \  m/s

Explanation:

From the question we are told that

   The child's weight is  W_c  =  287 \ N

    The length of the sliding surface of the playground is  L =  7.20 \  m

    The coefficient of friction is  \mu =  0.120

      The angle is \theta = 31.0 ^o

      The initial  speed is  u =  0.559 \  m/s

Generally the normal force acting on the child is mathematically represented as

=>    N  =  mg  *  cos \theta

Note  m *  g  =  W_c

Generally the frictional force between the slide and the child is    

         F_f  =  \mu *  mg  *  cos \theta

Generally the resultant force acting on the child due to her weight and the frictional  force is mathematically represented as

      F =m* g sin(\theta) - F_f

Here  F is the resultant force and it is represented as  F =  ma

=>   ma =   m* g sin(31.0)  - \mu *  mg  *  cos (31.0)

=>   a =  g sin(31.0)-  \mu *  g  *  cos (31.0)

=>  a =    9.8 *  sin(31.0) - 0.120 *  9.8  *  cos (31.0)

=>a =  4.039 \ m/s^2

So

   F_f  =  0.120  * 287  *  cos (31.0)

=> F_f  = 29.52 \  N

Generally the heat energy generated by the frictional  force which equivalent tot the workdone by the frictional force  is mathematically represented as

     H  =  F_f  * L

=>  H  = 29.52 *  7.2

=>  H  =212.6 \  J

Generally from kinematic equation we have that

    v^2  =  u^2  +  2as

=>  v^2  =  0.559^2  +  2 * 4.039 * 7.2

=>  v  =  \sqrt{0.559^2  +  2 * 4.039 * 7.2}

=>  v  =  7.647  \  m/s

   

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If a scale on Earth reads 650 N, what is your mass?
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Explanation:

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