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klemol [59]
3 years ago
14

If you weigh 690n on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and

a diameter of 19.0 km ?]
Physics
1 answer:
NeTakaya3 years ago
5 0
-- If you weigh 690N on the Earth, then your mass is about

           (690N) / (9.8 m/s²) = 70 kg .

-- If your mass is 70 kg then your weight on that neutron star would be

              G  M₁  M₂  /  R²

         =  (6.67 x 10⁻¹¹ N m²/kg²) (70 kg) (1.989 x 10³⁰ kg) / (19,000 m)²

         =  (6.67 x 10⁻¹¹ x 70 x 1.989 x 10³⁰) / (3.61 x 10⁸)        N

         =  (6.67 x 70 x 1.989 x 10¹⁹)  /  (3.61 x 10⁸)          N

         =    2.57 x 10¹³    Newtons .

  (about  2,890,000,000 tons !)
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3 0
3 years ago
Tidal friction is slowing the rotation of the Earth. As a result, the orbit of the Moon is increasing in radius at a rate of app
melomori [17]

Answer:

967500000 years

Explanation:

The Speed at which the radius of the orbit of the Moon is increasing is 4 cm/yr

Converting to m

1 m = 100 cm

1\ cm=\frac{1}{100}\ m

4\ cm\y=\frac{4}{100}=0.04\ m/yr

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Time = Distance / Speed

\text{Time}=\frac{3.87\times 10^7}{0.04}\\\Rightarrow \text{Time}=967500000\ yr

967500000 years will pass before the radius of the orbit increases by 10%.

7 0
3 years ago
What is the work of the force F (6.0N)(4.0N)j(-2.0N)k when the object moves from an initial point with coordinates (1.5 m, 3.0m,
Alina [70]

Answer:

option (c) - 10 j

Explanation:

F = (6 i + 4 j - 2 k) N

r1 = (1.5, 3, -4.5) m = (1.5 i + 3j - 4.5 k) m

r2 = (4, -2.5, - 3) m = (4 i - 2.5 j - 3 k) m

displacement, r = r2 - r1 = ( 2.5 i - 5.5 j + 1.5 k) m

Work done is defined as the dot product of force vector and teh displacement vector.

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W = (6 i + 4 j - 2 k) . ( 2.5 i - 5.5 j + 1.5 k)

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4 0
3 years ago
calculate the work done to stretch an elastic string by 40cm if a force of 10N produces an extension of 4cm in it?
Charra [1.4K]
100N is how much work is needed 
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3 years ago
When at rest, a ruler has a length of 12.0 inches. How fast (in m/s) must the ruler fly past you in order for it to shorten to 6
PIT_PIT [208]

Answer:

2.598×10^8 m/sec

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The length of the contraction is given by l=l_0\sqrt{1-\frac{v^2}{c^2}} here l_0 is length of the ruler at rest which is given as 12 inches

l is the length of the ruler in moving condition which is given as 6 inches c is the speed of the light and v is the velocity of the ruler.

l=l_0\sqrt{1-\frac{v^2}{c^2}}

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0.866=\frac{v}{c}

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3 0
3 years ago
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