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klemol [59]
3 years ago
14

If you weigh 690n on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and

a diameter of 19.0 km ?]
Physics
1 answer:
NeTakaya3 years ago
5 0
-- If you weigh 690N on the Earth, then your mass is about

           (690N) / (9.8 m/s²) = 70 kg .

-- If your mass is 70 kg then your weight on that neutron star would be

              G  M₁  M₂  /  R²

         =  (6.67 x 10⁻¹¹ N m²/kg²) (70 kg) (1.989 x 10³⁰ kg) / (19,000 m)²

         =  (6.67 x 10⁻¹¹ x 70 x 1.989 x 10³⁰) / (3.61 x 10⁸)        N

         =  (6.67 x 70 x 1.989 x 10¹⁹)  /  (3.61 x 10⁸)          N

         =    2.57 x 10¹³    Newtons .

  (about  2,890,000,000 tons !)
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The horizontal forces (With respect to the inclined plane) include the frictional force (acting upwards for the inclined plane, opposite to the intended direction of motion), the Tension in the rope (acting downwards, away from the 100 g block) and the horizontal component (with respect to the inclined plane) of the weight of the block, F, (also acting downards).

For the body to slide down the inclined plane at constant speed, the downward sloping forces must balance the frictional force, that is, there will be no acceleration.

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T = Fr - F = 0.568 - 0.253624 = 0.314376 N = 0.3144 N

But the balance on the rope now has the total weight on the container (weight of container + weight on the container) to be equal to 2T.

2T = mg

2 × 0.3144 = 9.8m

m = 0.06416 kg = 64.16 g.

Mass of the container = 30 g

So, mass that one should put in the container so that the 100 g block slides down the inclined plane at constant speed = 64.16 - 30 = 34.16 g

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