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Vladimir [108]
3 years ago
15

suppose two masses are connected by a spring. compute the formula for the trajectory of the center of mass of the two mass oscil

lator
Physics
1 answer:
Ymorist [56]3 years ago
8 0

Answer:

The center mass (Xcm) of the two mass = (M₁X₁ + M₂X₂)/(M₁ +M₂)

Explanation:

let the first mass = M

let the position of second  = M

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Frequency, period and wavelength<br> 11th grade high school physics
zzz [600]

Answer:0.38

Explanation:

the formula is f = c / λ

so f= 2.5/6.5

and that equals 0.38 46 and so on so i just rounded it

6 0
3 years ago
What’s the power if a student does 2240j of work for 2.8 seconds
Alex787 [66]

Answer:

800 Watts

Explanation:

Power = Work/time

Working in SI units, Power = Watts, Work = Joules, Time = seconds.

Power = 2240J/2.8s = 800 Watts.

7 0
3 years ago
How do we calculate the value of work?
Katarina [22]
The percent complete is calculated by dividing the quantity of material progressed at a point in time by the total quantity required for the project. The resulting percent is multiplied by the current agreed committed value of the material item to obtain the VOWD for that item.
7 0
3 years ago
Read 2 more answers
When friction slows a sliding block___
Svetradugi [14.3K]

Answer:

A

Explanation:

When friction slows a sliding block, <u>the kinetic energy of the block is transformed into internal energy .</u>

<em>The frictional movement of two surfaces over one another leads to the conversion of some of their kinetic energies to another energy - heat or thermal energy. Hence, the temperatures of the objects are raised in the process. </em>

<u>Therefore, when a sliding block is slowed down due to friction, some of the kinetic energy of the block would be transformed into internal energy in the form of heat.</u>

The correct option is A.

6 0
3 years ago
An object of mass 100kg is raised 2m above the ground using an Inclined Plane of length 10m calculate the effort parallel to inc
MArishka [77]

Answer:

Slope = 2 m / 10 m = 1/5

For every  5 m of effort the object will be raised 1 m

W = work done on object = M g h      increase in PE of object

E S = W      where E is effort and S the distance thru which the effort acts

E S = M g H

E = 100 kg * 9.8 m/s^2 * 2 m / 10 m = 196 kg m / s^2 = 196 N

Check: total work = 2 * 9.8 * 100 = 1960 J

Force Needed = 1960 J / 2 m = 980 Newtons

Mechanical advantage = 980 / 196 = 5   as one would expect since the object is raised 1 m for every 5 m of force input

8 0
2 years ago
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