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Vladimir [108]
3 years ago
15

suppose two masses are connected by a spring. compute the formula for the trajectory of the center of mass of the two mass oscil

lator
Physics
1 answer:
Ymorist [56]3 years ago
8 0

Answer:

The center mass (Xcm) of the two mass = (M₁X₁ + M₂X₂)/(M₁ +M₂)

Explanation:

let the first mass = M

let the position of second  = M

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When two waves are moving toward each other, and their crests line up with each other, it results in a wave with greater amplitu
Maurinko [17]

constructive interference

4 0
3 years ago
A scientist observes rock masses that have moved past each other in opposite horizontal directions. Which feature
Reil [10]

Answer:

C. strike-slip fault

Explanation:

The scientist must have observed a strike- slip fault.

A fault is an evidence of brittle deformation of the crust in the presence of applied stress on earth materials. Here, the earth material is the rock subjected to tension.

Where a fault occurs, there must have been movement between two blocks of rocks. The direction of movement helps us to delineate the fault type.

  • When two blocks moves past each other horizontally, it is a strike-slip fault like rubbing your palms together.
  • When a block moves in the direction of the dip, it forms a dip-slip fault which results in a fault-block mountain characterized by graben and horst systems.

Option A, Plateau is a table landform usually a mountain with flat peak.

Option B is a bowl shaped stratigraphic pattern in which the youngest sequence is at the core of the strata or a fold.

So, the most fitting option is C, a strike-slip fault.

8 0
2 years ago
Martine also has an eraser.it has a mass of 3g,and a volume if 1cm3.what is its density
shtirl [24]

Answer:

3g/cm³

Explanation:

<em>Use the formula:</em>

density = mass ÷ volume

<em>Substitute (plug in) the values:</em>

density = 3 ÷ 1 = 3g/cm³

4 0
2 years ago
A horizontal 810-N merry-go-round of radius 1.60 m is started from rest by a constant horizontal force of 55 N applied tangentia
Sloan [31]

Answer:

576 joules

Explanation:

From the question we are given the following:

weight = 810 N

radius (r) = 1.6 m

horizontal force (F) = 55 N

time (t) = 4 s

acceleration due to gravity (g) = 9.8 m/s^{2}

K.E = 0.5 x MI x ω^{2}

where MI is the moment of inertia and ω is the angular velocity

MI = 0.5 x m x r^2

mass = weight ÷ g = 810 ÷ 9.8 = 82.65 kg

MI = 0.5 x 82.65 x 1.6^{2}

MI = 105.8 kg.m^{2}

angular velocity (ω) = a x t

angular acceleration (a) = torque ÷ MI

where torque = F x r = 55 x 1.6 = 88 N.m

a= 88 ÷ 105.8 = 0.83 rad /s^{2}

therefore

angular velocity (ω) = a x t = 0.83 x 4 = 3.33 rad/s

K.E = 0.5 x MI x ω^{2}

K.E = 0.5 x 105.8 x 3.33^{2} = 576 joules

6 0
3 years ago
What mRNA sequence would result from the following DNA sequence?
Nezavi [6.7K]

Answer:

UAC CUG AGG AUC

Explanation:

<em>The mRNA sequence from ATG GAC TCC TAG DNA sequence would be </em><em>UAC CUG AGG AUC.</em>

<u>According to Chargaff's base pairing rule, the purine bases always pair with pyrimidine bases. Specifically, Adenine base must pair with Thymine base while Guanine base must pair with Cytosine base. In RNA, Thymine base is replaced with Uracil base.</u>

Hence:

ATG   GAC   TCC   TAG will pair with

UAC   CUG   AGG   AUC

5 0
3 years ago
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