Ask question

Ask question

All categories

2 years ago

15

suppose two masses are connected by a spring. compute the formula for the trajectory of the center of mass of the two mass oscil

lator

1 answer:

Ymorist [56]2 years ago

8 0

Answer:

The center mass (Xcm) of the two mass = (M₁X₁ + M₂X₂)/(M₁ +M₂)

Explanation:

let the first mass = M

let the position of second = M

You might be interested in

An engine moves a motorboat through water at a constant velocity of 22 meters/second. If the force exerted by the motor on the b

trapecia [35]

Answer: Option B: 1.3×10⁵ W

Explanation:

$Power = \frac{Work \hspace{1mm} done}{Time}$

$P=\frac{W}{t}$

Work Done, $W= F.s$

Where s is displacement in the direction of force and F is force.

$\Rightarrow P = \frac{F.s}{t} =F \times \frac{s}{t}=F.v$

where, v is the velocity.

It is given that, F = 5.75 × 10³N

v = 22 m/s

P = 5.75 × 10³N×22 m/s = 126.5 × 10³ W ≈1.3×10⁵W

Thus, the correct option is B

6 0

2 years ago

Ari, a young patient who is regularly treated by a psychiatrist, feels compelled to carry out repetitive tasks the same way very

blondinia [14]

OCD would probably be the answer.

5 0

2 years ago

Read 2 more answers

A force of 100 newtons is used to move an object a distance of 15 meters with a power of 25 watts. Find the

valentina_108 [34]

work is distance * force so 15*100=1500

and to find time you know power = diastance * force / time

so 25=15*100/t

25=1500/t

25/1500=t

.016=time

5 0

2 years ago

The electric current in a copper wire is composed of what

Tanzania [10]

Answer:

A copper wire current consists of electrons appropriately called conduction electrons.

Explanation:

This answer came from quizlet.com. I hope that this helps you and good luck!

8 0

2 years ago

Two capacitors, a 15 micro F and a 25 micro F, are connected in parallel to a 60 Hz source. The total capacitive reactance is :_

Stells [14]

Answer:

<em> 3980.89 ohms</em>

Explanation:

The capacitive reactance is expressed as;

$X_c = \frac{1}{2 \pi fC}$

f is the frequency

C is the capacitance of the capacitor

Given

f = 60H

C = C1+C2 (parallel connection)

C = 15μF + 25μF

C = 40μF

C = $40 * 10^{-6}F$

Substitute into the formula:

$X_c = \frac{1}{2(3.14)*60*40*10^{-6}}\\X_c = \frac{1}{0.0002512}\\X_c = 3,980.89$

<em>Hence the total capacitive reactance is 3980.89 ohms</em>

5 0

2 years ago