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noname [10]
3 years ago
5

For an amino acid such as aspartic acid, what impact would you expect a neighboring carboxylic acid to have on the apparent pKa

value of the side chain?
Chemistry
1 answer:
tekilochka [14]3 years ago
7 0

Answer:

The apparent pKa value for aspartic acid increases

Explanation:

The apparent pKa value for aspartic acid increases.  Due to the presence of one negative in close proximity to another negative charge, it causes charge-to-charge repulsion which in turn leads to the increase in pKa values.

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Please indicate which of the compounds will yield postive results for the permanganate, ninhydrin, and ceric ammonium nitrate te
maks197457 [2]

The compounds will yield Positive results for the permanganate, ninhydrin, and ceric ammonium nitrate tests  are

permanganate test= ethene,

ninhydrin=aspasyic acid Phenylalanine

ceric ammonium nitrate test= methanol

<h3>What is a compound?</h3>

Generally, A compound is simply defined as a substance made up of two or more different chemical elements held together by chemical bonds that are difficult to break.

In conclusion, For the permanganate test= ethene,

ninhydrin=aspasyic acid Phenylalanine

ceric ammonium nitrate test= methanol

Read more about Compound

brainly.com/question/704297

3 0
2 years ago
If a plant produces 8.46 mol C6H12O6, how many moles of H2O are needed?
Ierofanga [76]

Answer:

50.76 mol H2O.

Explanation:

The photosynthesis follows the equation:

6CO2 + 6H2O ---> C6H12O6 + 6O2

This means that 6 mol of H2O are needed to obtain 1 mol of C6H12O6 (see the numbers that precedes every molecule to know how many mols are in game).

So we can say that:

1 mol C6H12O6 --------- 6 mol H2O

8.46 mol C6H12O6 -----x= 8.46 x 6 : 1 = 50.76 mol H20

8 0
3 years ago
This decomposition is first order with respect to phosphine, and has a half‑life of 35.0 s at 953 K. Calculate the partial press
Solnce55 [7]

Answer:

0.57 atm

Explanation:

When a a reaction is first order, we have from calculus the following relation:

ln[A]t/[A]₀ = - kt

where [A]t is the concentration of A ( phosphine in this case ) after a time, t

           [A]₀ is the initial concentration of A

           k is the rate constant, and

           t is the time

We also know that for a first order reaction

           k = 0.693/ t 1/2

wnere t 1/2 is the half-life.

This equation is derived for the case when A]t/= 1/2 x [A]₀ which occurs at the half-life.

Thus, lets first find k from the half life time, and then solve for t = 70.5 s

k = 0.693 /  35.0 s = 0.0198 s⁻¹

ln [ PH₃ ]t / [ PH₃]₀ = - kt

from the ideal gas law we know pV = nRT, so the volumes cancel:

ln (pPH₃ )t / p(PH₃)₀ = - kt

taking inverse log to both sides of the equation:

(pPH₃ )t / p(PH₃)₀  = - kt

thus:

(pPH₃ )t  = 2.29 atm x e^(- 0.0198 s⁻¹ x 70.5 s ) = 0.57 atm

3 0
3 years ago
Someone pls help me I will make you brain
Katena32 [7]

Answer:

it is actually b because i did this i picked b and got it right

Explanation:

4 0
3 years ago
A self-contained underwater breathing apparatus (SCUBA) uses canisters containing potassium superoxide. The superoxide consumes
emmainna [20.7K]

Answer:

52.0004 grams of mass of potassium superoxide  is required

Explanation:

Let moles carbon dioxide gas be n at 22.0 °C and 767 mm Hg occupying 8.90 L of volume.

Pressure of the gas,P = 767 mm Hg = 0.9971 atm

Temperature of the gas,T = 22.0 °C = 295.15 K

Using an ideal gas equation to calculate the number of moles.

PV=nRT

n=\frac{0.9971 atm\times 8.90 L}{0.0821 atm L/mol K\times 295.15 K}

n = 0.3662 mol

4KO_2(s)+2CO_2(g)\rightarrow 2K_2CO_3(s)+3O_2(g)

According to reaction, 2 moles of carbon-dioxide reacts with 4 moles of potassium superoxide.

Then 0.3662 mol of  of carbon-dioxide will react with:

\frac{4}{2}\times 0.3662 mol=0.7324 mol of potassium superoxide.

Mass of 0.7324 mol potassium superoxide:

0.7324 mol × 71 g/mol = 52.0004 g

52.0004 grams of mass of potassium superoxide is required.

8 0
3 years ago
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