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noname [10]
3 years ago
5

For an amino acid such as aspartic acid, what impact would you expect a neighboring carboxylic acid to have on the apparent pKa

value of the side chain?
Chemistry
1 answer:
tekilochka [14]3 years ago
7 0

Answer:

The apparent pKa value for aspartic acid increases

Explanation:

The apparent pKa value for aspartic acid increases.  Due to the presence of one negative in close proximity to another negative charge, it causes charge-to-charge repulsion which in turn leads to the increase in pKa values.

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Determine the enthalpy change for the reaction 2C(s) + 2H2O(g) → CH4(g) + CO2(g) using the following:
Sophie [7]

Answer : The enthalpy change for the reaction is, 97.7 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given main chemical reaction is,

2C(s)+3H_2O(g)\rightarrow CH_4(g)+CO_2(g)    \Delta H=?

The intermediate balanced chemical reaction will be,

(1) C(s)+H_2O(g)\rightarrow CO(g)+H_2(g)     \Delta H_1=131.3kJ

(2) CO(g)+H_2O(g)\rightarrow CO_2(g)+H_2(g)    \Delta H_2=41.2kJ

(3) CH_4(g)+H_2O(g)\rightarrow 2H_2(g)+CO(g)    \Delta H_3=206.1kJ

Now we are multiplying reaction 1 by 2 and reversing reaction 3 and then adding all the equations, we get :

(1) 2C(s)+2H_2O(g)\rightarrow 2CO(g)+2H_2(g)     \Delta H_1=2\times 131.3kJ=262.6kJ

(2) CO(g)+H_2O(g)\rightarrow CO_2(g)+H_2(g)    \Delta H_2=41.2kJ

(3) 2H_2(g)+CO(g)\rightarrow CH_4(g)+H_2O(g)    \Delta H_3=-206.1kJ

The expression for enthalpy of main reaction will be,

\Delta H=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H=(262.6)+(41.2)+(-206.1)

\Delta H=97.7kJ

Therefore, the enthalpy change for the reaction is, 97.7 kJ

3 0
3 years ago
Read 2 more answers
Identify the element of Period 2 which has the following successive ionization energies, in kJ/mol. IE1, 1314 IE2, 3389 IE3, 529
Elan Coil [88]
It’s fluorine it has a big jump from the 6th to 7th ionisation energy.

It’s electronic configuration is 1s2 2s2 2p5 as it has 9 electrons and 7 electrons in outermost shell.

Therefore it’s in group 7, as after the 7 electrons are removed, the 8th electron is removed from a quantum shell closer to the nucleus.

This results in greater ionisation energy due to stronger electrostatic forces of attraction between positively charge nuclei and electrons ( + shorter distance)
6 0
3 years ago
Which of the following hydrocarbons has a double bond in its carbon skeleton?1) C3H82) C2H63) CH44) C2H45) C2H2
Kipish [7]

Answer:

  • <u>C₂H₄</u>  (option number 4)

Explanation:

A hydrocarbon with a <em>double bond</em> in its carbon skeleton is an alkene and has the general form:

  • C_nH_{2n}.

This is, the number of hydrogen atoms is twice the number of carbon atoms.

On the other hand, alkanes have only single bonds, and the compounds with a triple bond in its carbon skeleton are alkynes.

Review each choice:

1) <u>C₃H₈:</u>

  • In this case, the number of hydrogen atoms is 2×3 + 2 = 6 + 2 = 8, which is corresponds to an alkane, not an alkene.

2)<u> C₂H₆</u>

  • For this, the number of hydrogen atoms is 2 × 2 + 2 = 4 + 2 = 6. Again an alkane, not alkene.

3) <u>CH₄</u>

  • Hydrogen atoms: 1 × 2 + 2 = 4 ⇒ an alkane

4) <u>C₂H₄ </u>

  • Hydrogen atoms: 2 × 2  = 4.  This is precisely the relation for an alkene, so this is the hydrocarbon that has a double bond in its carbon skeleton.

  • The chemical formula may be writen as CH₂ = CH₂, to show the double bond.

So, this is the correct answer.

5) <u>C₂H₂</u>

  • Hydrogen atoms: 2 × 2 - 2 = 4 - 2 = 2. This relation of carbon and hydrogen atoms corresponds to a compound with triple bond, i.e an alkyne: CH≡CH.
8 0
3 years ago
The graph above represents an object moving with a __________________. A) constant velocity B) constant acceleration C) constant
Ann [662]

Answer: I think its C or B

Explanation: Hope this was helpful....

4 0
3 years ago
Lakesha gave three tenths of her cookies to Bailey and five tenths of her cookies to Helen. What fraction of her cookies did Lak
Mashutka [201]

Answer:

a . eight tenths of her cookies

Explanation:

Let the total number of Lakesha's cookies be represented by x.

So that;

She gave three tenths to Bailey = \frac{3}{10} of x

                                                     = \frac{3x}{10}

She gave five tenths to Helen = \frac{5}{10} of x

                                                  = \frac{5x}{10}

Fraction of Lakesha's cookies given away = \frac{3x}{10} + \frac{5x}{10}

                                                      = \frac{3x+ 5x}{10}

                                                      = \frac{8x}{10}

Thus, the fraction of cookies given away by Lakesha is \frac{8}{10}.

6 0
3 years ago
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