I just looked it up and it says "Na2CO3 (sodium carbonate) is neither an acid nor a base. It is a salt..." I really hoped this helped you, if not I'm sorry.
Let <span>A= ebc </span>
<span> 0.765 = 86,300*1.3*c </span>
<span>
Solve for c = approximately 7E-6 Molar
= mols/L soln. </span>
<span>g = 7E-6*893.49
= about 0.006 g chlorophyll/L soln. </span>
<span>
1000 x 0.785 = 785 g ethanol. </span>
<span>Conc. = about 0.006g chlorophyll/785 g soln. </span>
<span>
Change that to ppm. by using formula:
(0.006/785)*1E6</span>
Electrons are (-) and Protons are (+)
Answer: The Eurasian Plate or both the Eurasian and Pacific Plate.
Explanation:
Since there is no weight, I would assume that this is a 100g of pure compound.
Okay so I would be changing the percentage to gram to solve for the mole.
So
40.0g C (1 mol C/12.01 g C) = 3.33 mol C
6.73g H (1 mol H/1.01 g H ) = 6.66 mol H
53.3g O (1 mol O/16.00 g O) = 3.33 mol O
With that, two of our moles is 3.33, so we consider that are our 1, as it is also the lowest. Therefore the empirical formula is CH2O
