Answer:
3/14
Step-by-step explanation:
hope this helps
Answer:
6) x=9.75
10) Triangle OMN ~ Triangle ODK; SSS ~
11) SSS ~ theorem
12) SSS ~ theorem
Step-by-step explanation:
For #6, since the polygons are similar, then it must mean AD is congruent to JM and CD is congruent to LM. Now we can set up the proportion 39/20=x/5 and solve. Solving for x gets us x=9.75, so C is the correct choice
For #10, there's no information about angles whatsoever in the diagram, so B and C must be wrong. D must be wrong as well because if the triangles weren't similar, then why is OJ ~ JM and OK ~ KN? So thus, the triangles are similar by SSS.
For #11, this is sort of a no-brainer because there's no mention of angles, so D must be correct.
For #12, same concept, no mention of angles, all sides are similar to their respective sides of the different triangles, so A is correct.
Answer:
1 3/12
Step-by-step explanation:
Oh wait i could read #5 so you make them all have 12 as the denominator then do 78 4/12 - 77 1/12 and you get 1 1/4 or 1 3/12 so then you do 1 3/12 MINUS 77 1/12 and you should get 75 10/12 which is CORRECCTTTTT
THESE ARE THE THREE IN THE TEXT ORDER IN CASE U NEED TO SEE
78 4/12
77 1/12
75 10/12
EVERYTHING IS CORRECTTTTTTTTTTTTTTTTTTTTTT
2 is the base and (
![\sqrt[4][a^5 b^3]](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%5Ba%5E5%20b%5E3%5D)
) is the exponent.
the 4 is called an index and it means to fi d the fourth root of the expression under the (
![\sqrt[][text]) symbol.\\a fourth root is a factor that was multiplied four times. ex: 2*2*2*2=16. the fourth root of 16 is two. \\when you do square roots, you take the number representing the factor out of the radical. anything else that is not a square root stays under. ex: \\([tex]\sqrt[9][text])\\([tex]\sqrt[3*3*3][text]) there is one set of two 3's so\\([tex]3\sqrt[3][text])\\with a fourth root, you look for groups of four. the symbol of that group is placed outside the radical. anything else stays in.\\ ([tex]\sqrt[4][a^5 b^3]](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%5Btext%5D%29%20symbol.%5C%5Ca%20fourth%20root%20is%20a%20factor%20that%20was%20multiplied%20four%20times.%20ex%3A%202%2A2%2A2%2A2%3D16.%20the%20fourth%20root%20of%2016%20is%20two.%20%5C%5Cwhen%20you%20do%20square%20roots%2C%20you%20take%20the%20number%20representing%20the%20factor%20out%20of%20the%20radical.%20anything%20else%20that%20is%20not%20a%20square%20root%20stays%20under.%20ex%3A%20%5C%5C%28%5Btex%5D%5Csqrt%5B9%5D%5Btext%5D%29%5C%5C%28%5Btex%5D%5Csqrt%5B3%2A3%2A3%5D%5Btext%5D%29%20there%20is%20one%20set%20of%20two%203%27s%20so%5C%5C%28%5Btex%5D3%5Csqrt%5B3%5D%5Btext%5D%29%5C%5Cwith%20a%20fourth%20root%2C%20you%20look%20for%20groups%20of%20four.%20the%20symbol%20of%20that%20group%20is%20placed%20outside%20the%20radical.%20anything%20else%20stays%20in.%5C%5C%20%28%5Btex%5D%5Csqrt%5B4%5D%5Ba%5E5%20b%5E3%5D)
)
(
![\sqrt[4][a*a*a*a*a*b*b*b]](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%5Ba%2Aa%2Aa%2Aa%2Aa%2Ab%2Ab%2Ab%5D)
) there is one group of 4 a's so
(
![a\sqrt[4][a* b^3]](https://tex.z-dn.net/?f=a%5Csqrt%5B4%5D%5Ba%2A%20b%5E3%5D)
)
there really isn't anything else to do to simplify the expression
D=ab-c Theres your answer
a-1<span />
