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evablogger [386]
3 years ago
8

Solve -9 2/7 - (-10 3/7). A. - 1 1/7 B. 1 1/7 C. 19 1/7 D. 19 5/7

Mathematics
1 answer:
jenyasd209 [6]3 years ago
6 0

Answer:

1 5/7

Step-by-step explanation:

-9 2/7 -(-10 3/7) recall -×- = +

-9 2/7 +10 3/7

1 2+3/7

1 5/7

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If f(x) = 3x + 2, what is f(5)?​
MrRa [10]

Answer:

f(5) = 17

Step-by-step explanation:

plug in 5 in the x so 3(5)+2 =17

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3 years ago
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Find what n equals 8(2n-2) = 4 - 4n (explanation please)
slavikrds [6]

Answer:

\huge\boxed{n=1}

Step-by-step explanation:

In order to find the value of n that satisfies this equation, we can perform a series of algebraic steps on it to solve for n.

  • 8(2n-2) = 4- 4n
  • <em>Distribute in the 8 on the left side:</em>
  • <em />16n-16=4-4n<em> </em>
  • <em>Add 4n to both sides</em>
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  • <em>Add 16 to both sides</em>
  • 20n = 20
  • <em>Divide both sides by 20</em>
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Therefore, n=1 is the value of n that satisfies this equation.

Hope this helped!

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3 years ago
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Q1W7 Learning Task 1 (Introduction)
Tatiana [17]

Answer:

Column A                                            Column B

1. x² + 6x + 8                                        x-3,x+2

2. x³ - 7x + 6                                       x+1, x+2, x+3

3. x³ - 2x² - 5x + 6                              x-1, x+2, x-3

Step-by-step explanation:

Column A                                            Column B

1. x² + 6x + 8                                        x-3,x+2

2. x³ - 7x + 6                                       x+1, x+2, x+3

3. x³ - 2x² - 5x + 6                              x-1, x+2, x-3

Using Factor theorem we put values of x = ±1,±2,±3 in each of the polynomials unless we get a zero.

1. x² + 6x + 8      

= 1+6(1) +8= 15

1. x² + 6x + 8

  4+ 12+8 = 24

1. x² + 6x + 8

 (-1)² + 6(-1)+ 8

= 1-6+8= 3

1. x² + 6x + 8

 (-2)² + 6(-2)+ 8

= 4-12+8= 0

1. x² + 6x + 8

(3)²+ 6(3) +8

= 9+18+8 ≠ 0

1. x² + 6x + 8

(-3)²+ 6(-3) +8

= 9-18+8 =-1

For this polynomial we have x+2= 0 or x=-2, x-3= 0 , x=3

2. x³ - 7x + 6

1-7+6= 0

2. x³ - 7x + 6

(-1)³-7(-1) +6

= 13-1≠0

2. x³ - 7x + 6

(2)³-7(2) +6

= 8-14+6= 0

2. x³ - 7x + 6

(-2)³-7(-2) +6

= -8 +14+6

2. x³ - 7x + 6

(-3)³-7(-3) +6

= -27+21+6 = 0

For this polynomial we have x+1= 0 , x+2 = 0  and x+3= 0, or x=-1,-2,-3

3. x³ - 2x² - 5x + 6

(1)³-2(1)²-5(1)+6

= 0

3. x³ - 2x² - 5x + 6

(-1)³-2(-1)²-5(-1)+6

= -1 -2 +5+6

=8

3. x³ - 2x² - 5x + 6

(2)³-2(2)²-5(2)+6

= 8-8-10+6

=-4

3. x³ - 2x² - 5x + 6

(-2)³-2(-2)²-5(-2)+6

= -8-8+10+6

=0

3. x³ - 2x² - 5x + 6

(3)³-2(3)²-5(3)+6

= 27-18-15+6

=0

3. x³ - 2x² - 5x + 6

(-3)³-2(-3)²-5(-3)+6

= -27-18+15+6

=-14

For this polynomial we have x-1= 0 ,x+2=0, x-3= 0or x=1,-2,3

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You are deciding between two cars with different engines and want the bigger
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Answer:

2

Step-by-step explanation:

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