Answer:
Y = 40.94m
Explanation:
The initial speed of the sandbag is the same as the balloon and so is its position, so:
Replacing these values:
Yo = 40m Vo = 5m/s g = 9.81m/s^2 t = 0.25s
We get the position of the sandbag:
Y = 40.94m
PLS I NEED HELP ASAP!!!
1 answer:
You might be interested in
B) initial speed (u)=3
final speed (v)=8
time (t)= 10
acceleration (a)=?
v=u+at
8=3+a(10)
5=10a
a=1/2= 0.5 m/s²
c)displacement (s)=?
1st section of journey
v ²=u ²+2as
8 ²=3 ²+2(0.5)s
64=9+1s
s=55meters
2nd section of journey
a=0
t=7
u=8
s=?
s=ut+1/2at²
s=8(7)+1/2(0)(7 ²)
s=56 meters
56+55= 111 meters
(For graph x axis =time (sec) & y axis= velocity (m/s))
final speed (v)=8
time (t)= 10
acceleration (a)=?
v=u+at
8=3+a(10)
5=10a
a=1/2= 0.5 m/s²
c)displacement (s)=?
1st section of journey
v ²=u ²+2as
8 ²=3 ²+2(0.5)s
64=9+1s
s=55meters
2nd section of journey
a=0
t=7
u=8
s=?
s=ut+1/2at²
s=8(7)+1/2(0)(7 ²)
s=56 meters
56+55= 111 meters
(For graph x axis =time (sec) & y axis= velocity (m/s))