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stich3 [128]
3 years ago
10

PLS I NEED HELP ASAP!!!

Physics
1 answer:
stellarik [79]3 years ago
7 0

Answer:

m

Explanation:

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A 56.0kg ice skater spins about a vertical axis through her body with her arms horizontally outstretched, making 2.50 turns each
Arada [10]

Answer:

Net force = 129.4, Force as multiple of weight of her hand = 18.84

Explanation:

Given Data:

Total body weight = 56.0 kg   ;

no. of turns = 2.5/second        ;

hand to hand distance = 1.5m ;

weight of hand = 1.25% of body weight ;

Solution:

mass of hand = \frac{1.25}{100}*56 = 0.7kg ;

radius = d/2 = 1.5/2 = 0.75m     ;

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v = d/t = \frac{2.5*2*3.14*0.75}{1} = 11.775 m/s or 12 m/s;

a.

The formula to calculate force is given as

F = mv²/r = (0.7*11.775²)/0.75 = 129.4 N

b.

To calculate force as multiple of weight on her hand, we need to calculate the gravitational force W on her hand first.

W = gm = 9.81 * 0.7 = 6.867 N

Now the wieght on her hand can be represented by

\frac{Force_{net} }{weight of hand}  = 129.4 / 6.867 = 18.84

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Aye, I'm b0red so here's an easy one:
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ok

1. blue red pink black

2. you can say bored look

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