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Katarina [22]
2 years ago
10

Which resource would be the best choice to learn more information about studying martial arts?

Physics
1 answer:
Mekhanik [1.2K]2 years ago
3 0

I think videos help more than books when it comes to martial arts. You can get it on YouTu.be if your teacher doesn't teach you online, in this pandemic.

You might be interested in
A guitar string vibrates at a frequency of 330Hz with wavelength 1.40m. The frequency and wavelength of this sound wave in air (
bixtya [17]

Answer:

Same frequency, shorter wavelength

Explanation:

The speed of a wave is given by

v=f\lambda

\lambda=\dfrac{v}{f}

where,

f = Frequency

\lambda = Wavelength

It can be seen that the wavelength is directly proportional to the velocity.

Here the frequency of the sound does not change.

But the velocity of the sound in air is slower.

Hence, the frequency remains same and the wavelength shortens.

7 0
3 years ago
The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: =E−Ryn2 In this equation Ry stands for
skelet666 [1.2K]

Answer:

  λ = 162 10⁻⁷ m

Explanation:

Bohr's model for the hydrogen atom gives energy by the equation

         E_{n} = - k²e² / 2m (1 / n²)

Where k is the Coulomb constant, e and m the charge and mass of the electron respectively and n is an integer

The Planck equation

           E = h f

The speed of light is

          c = λ f

          E = h c /λ

For a transition between two states we have

          E_{n} - E_{m} = - k²e² / 2m (1 / n_{f}² -1 / n_{i}²)

           h c / λ = -k² e² / 2m (1 / n_{f}² - 1/ n_{i}²)

           1 / λ = (- k² e² / 2m h c) (1 / n_{f}² - 1/n_{i}²)

The Rydberg constant with a value of 1,097 107 m-1 is the result of the constant in parentheses

Let's calculate the emission of the transition

            1 /λ = 1.097 10⁷ (1/10² - 1/8²)

            1 / λ = 1.097 10⁷ (0.01 - 0.015625)

            1 /λ = 0.006170625 10⁷

            λ = 162 10⁻⁷ m

3 0
3 years ago
Traveling waves are generated on a string fixed at both ends. The string has a length L, a linear mass density m, and a tension
bagirrra123 [75]

Answer: d. I or II

Explanation: A traveling wave has speed that depends on characteristics of a medium. Characteristics like linear density (μ), which is defined as mass per length.

Tension or Force (F_{T}) is also related to the speed of a moving wave.

The relationship between tension and linear density and speed is ginve by the formula:

|v|=\sqrt{\frac{F_{T}}{\mu} }

So, for the traveling waves generated on a string fixed at both ends described above, ways to increase wave speed would be:

1) Increase Tension and maintaining mass and length constant;

2) Longer string will decrease linear density, which will increase wave speed, due to their inversely proportional relationship;

Then, ways to increase the wave speed is

I. Using the same string but increasing tension

II. Using a longer string with the same μ and T.

8 0
2 years ago
An advertisement claims that a particular automobile can "stop on a dime". What net force would actually be necessary to stop an
Luba_88 [7]

Answer:

F = 4399 KN

Explanation:

given,

mass of automobile = 890 kg

initial speed = 48 km/h

                     = 48 × 0.278 = 13.34 m/s

using equation of motion

v² = u² + 2 a × s

0 = 13.34² - 2 a ×0.018

a = \dfrac{13.34^2}{0.036}

a = 4943.21 m/s²

F   = m × a

F   = 890 × 4943.21

F   =  4399456.9 N

F = 4399 KN

hence, the  Net force is F = 4399 KN

4 0
3 years ago
Orbitals that are of equal energy may be referred to as.
ivanzaharov [21]

Answer:

degenerate

Explanation:

5 0
2 years ago
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