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3 years ago

Chemistry: hydroluronic acid formula

Mathematics

1 answer:

lara [203]3 years ago

4 0

Answer:(C14H21NO11)n

Step-by-step explanation:

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Someone help please

pav-90 [236]

Answer:

7.76

Step-by-step explanation:

tan 29° = XY/14

XY = tan 29° (14)

= 7.76

5 0

3 years ago

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Divide. Write the answer in simplest form 1/8 divided by 1/4

andreev551 [17]

1/8*4=4/8=1/2--> the correct answer to this equation.

5 0

3 years ago

Drag and drop the descriptions into the boxes to correctly classify each pair of numbered angles. Each description may be used m

Alenkasestr [34]

The first box is "none of these" since it is not a vertical angle, is not an adjacent angles, and is not a linear pair, the second box is vertical angles

3 0

3 years ago

Read 2 more answers

A snack mix recipe calls for 2 1/5 cups of sugar and 1/5 cup of cinnamon Anthony wants to make the same recipe using one cup of

BaLLatris [955]

Answer:Culinary Math. 2-13 tsp (t) teaspoon tbsp (T) tablespoon c cup pt pint ..... granulated sugar ..... the recipe calls for 2 cups of flour, you would need to convert to.

Step-by-step explanation: I had a this question and i got it correct but if u not looking for this SORRY!

I HOPE I HELP YOUU!!1

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3 years ago

The Institute of Education Sciences measures the high school dropout rate as the percentage of 16- through 24-year-olds who are

STALIN [3.7K]

Answer:

We conclude that the proportion of dropouts has changed from the historical value of 0.081.

Step-by-step explanation:

We are given that in 2009, the high school dropout rate was 8.1%. A polling company recently took a survey of 1000 people between the ages of 16 and 24 and found 6.5% of them are high school dropouts.

The polling company would like to determine whether the proportion of dropouts has changed from the historical value of 0.081.

Let p = proportion of school dropouts rate

SO, Null Hypothesis, $H_0$ : p = 0.081 {means that the proportion of dropouts has not changed from the historical value of 0.081}

Alternate Hypothesis, $H_A$ : p $\neq$ 0.081 {means that the proportion of dropouts has changed from the historical value of 0.081}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of high school dropout rate = 6.5%

n = sample of people = 1000

So, test statistics = $\frac{0.065-0.081}{{\sqrt{\frac{0.065(1-0.065)}{1000} } } } }$

= -2.05

Also, P-value is given by the following formula;

P-value = P(Z < -2.05) = 1 - P(Z $\leq$ 2.05)

= 1 - 0.97982 = 0.0202 or 2.02%

Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test. Since our test statistics does not lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the proportion of dropouts has changed from the historical value of 0.081.

7 0

4 years ago