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gayaneshka [121]
3 years ago
9

The reaction below can be catalyzed by manganese dioxide (MnO2). If you carried out such a reaction, which compound would you ex

pect to find in the reaction container at the end of the reaction?
2H2O2 ?2H2O + O2

A. MnO

B. MnH2

C. MnO2

D. MnOH
Chemistry
1 answer:
coldgirl [10]3 years ago
8 0

Answer:

\boxed{\text{C. MnO$_{2}$}}

Explanation:

2H₂O₂ ⟶ 2H₂O + O₂

A catalyst is a substance that speeds up a reaction but can be recovered unchanged at the end.

Thus, at the end of the reaction I would expect to find H₂O and MnO₂ in the container.

Water is not listed in any of the options, so I will have to choose \boxed{\text{C. MnO$_{2}$}}.

A, B, and D are wrong. They are not reactants, products, or catalysts.

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The ph after 17.0 ml of 0.15 m Koh has been added to 15 ml of 0.20 m hclo4 is  <u>3.347</u>.

Titration is a commonplace laboratory technique of quantitative chemical analysis to determine the attention of an identified analyte. A reagent, termed the titrant or titrator, is ready as a trendy answer of recognized awareness and extent.

<u>Calculation:-</u>

Normality of acid                                               Normality of base

= nMV                                                                        nMV

= 1 × 0. 15 × 0.017                                              1 ×  0. 20 ×0.015 L

= 2.55 × 10⁻³                                                             = 3 × 10⁻³

The overall base will be high

net concentration = 3× 10⁻³ - 2.55 × 10⁻³

                             = 0.45 × 10⁻³

                             = 4.5× 10⁻⁴

pH = -log[4.5 × 10⁻⁴]

    = 4 - log4.4

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A titration is defined as 'the manner of determining the amount of a substance A by using adding measured increments of substance B, the titrant, with which it reacts till precise chemical equivalence is completed the equivalence factor.

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7 0
1 year ago
Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 4.90 moles of magnesium perchlorate, Mg(ClO4)2.]\
Leviafan [203]

Answer:

 4.90  moles of  Mg(ClO_4)_2   will produce  (9.8) moles of  Cl^{-} ,

                                                    (4.90) moles of Mg^{2+} and

                                                    (39.2) moles of  O^{2-}

Explanation:

From the question we are told that

  The number of moles of  is  n =  4.90  \ mols

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From the reaction we see that

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   4.90  moles of  Mg(ClO_4)_2   will produce  (2 * 4.90) moles of  Cl^{-} ,

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So

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