The reaction below can be catalyzed by manganese dioxide (MnO2). If you carried out such a reaction, which compound would you ex
1 answer:
Answer:
Explanation:
2H₂O₂ ⟶ 2H₂O + O₂
A catalyst is a substance that speeds up a reaction but can be recovered unchanged at the end.
Thus, at the end of the reaction I would expect to find H₂O and MnO₂ in the container.
Water is not listed in any of the options, so I will have to choose .
A, B, and D are wrong. They are not reactants, products, or catalysts.
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Answer:
[C₆H₅COO⁻][H₃O⁺]/[C₆H₅COOH] = Ka
Explanation:
The reaction of dissociation of the benzoic acid in water is given by the following equation:
C₆H₅-COOH + H₂O ⇄ C₆H₅-COO⁻ + H₃O⁺ (1)
The dissociation constant of an acid is the measure of the strength of an acid:
HA ⇄ A⁻ + H⁺ (2)
(3)
<em>Where the dissociation constant of the acid (Ka) is equal to the ratio of the concentration of the dissociated forms of the acid, [A⁻][H⁺], and the concentration of the acid, [HA]. </em>
So, starting from the equations (2) and (3), the constant equation for the dissociation reaction of benzoic acid in water, of the equation (1), is:
I hope it helps you!