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max2010maxim [7]
3 years ago
7

How does a chemical reaction obey the law of conservation of matter?

Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

Answer:

Normally, it explains that matter cannot be created or destroyed. It demonstrates different chemical reactions that help show the different transformations of the matter but will never destroy it or create it.

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Which statement best describes the development of theories that connected microscopic and macroscopic phenomena?
Alina [70]

The statement which best describes the development of theories that connected microscopic and macroscopic phenomena is; <em>q</em><em>It took several hundred years for scientists to develop current theories, and they are still being revised to </em><em>this.</em>

<em>Discussion</em><em>;</em>

Most scientific theories involving microscopic and macroscopic phenomenon have taken several years to be developed; however, this theories are still under revision till date.

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brainly.com/question/13407374

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3 years ago
Please help me with these problems I am almost done with homework
Klio2033 [76]
4 Living organisms contain relatively large amounts of oxygen, carbon, hydrogen,nitrogen, and sulfur (these five elements are known as the bulk elements), along with sodium, magnesium, potassium, calcium,chlorine, and phosphorus (these six elements are known as macro minerals).

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3 years ago
1. How many joules must be added to 10.0 g of water to raise its temperature from 10°C to<br> 15°C?
weqwewe [10]

Answer:

209.3 Joules require to raise the temperature from 10 °C to 15 °C.

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m × c × ΔT

Given data:

mass of water = 10 g

initial temperature T1= 10 °C

final temperature T2=  15 °C

temperature change =ΔT= T2-T1 = 15°C - 10°C = 5 °C

Energy or joules added to increase the temperature Q = ?

Solution:

We know that specific heat of water is 4.186 J/g .°C

Q = m × c × ΔT

Q = 10 g × 4.186 J/g .°C × 5 °C

Q = 209.3 J

6 0
3 years ago
Hydrogen peroxide can act as either an oxidizing agent or a reducing agent depending on the species present in solution. Write t
Gekata [30.6K]

Answer:

Reduction: 2 H⁺(aq) + H₂O₂(aq) + 2 e⁻ ⇒ 2 H₂O(l)

Oxidation: H₂O₂(aq) ⇒ O₂(g) + 2 H⁺(aq) + 2 e⁻

Explanation:

In H₂O₂, hydrogen has the oxidation number +1 and oxygen the oxidation number -1.

In the reduction half-reaction (H₂O₂ is the oxidizing agent), H₂O₂ forms H₂O. The oxidation number of oxygen decreases from -1 to -2.

2 H⁺(aq) + H₂O₂(aq) + 2 e⁻ ⇒ 2 H₂O(l)

In the oxidation half-reduction (H₂O₂ is the reducing agent), H₂O₂ forms O₂. The oxidation number of oxygen increases  from -1 to 0.

H₂O₂(aq) ⇒ O₂(g) + 2 H⁺(aq) + 2 e⁻

3 0
3 years ago
Why are animals so impportant to our lifes
ivann1987 [24]

Answer:

Animals are important because without them we wouldnt have any food

Explanation:

5 0
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