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max2010maxim [7]
3 years ago
7

How does a chemical reaction obey the law of conservation of matter?

Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

Answer:

Normally, it explains that matter cannot be created or destroyed. It demonstrates different chemical reactions that help show the different transformations of the matter but will never destroy it or create it.

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Is fluber liquid or solid
Gennadij [26K]
Nor liquid or solid since flubber is like oobleck, it is a non newtonian object.
3 0
3 years ago
Read 2 more answers
Three chemical reactions of ethane?
Otrada [13]

Answer:

1.Hydrogenation of Alkenes and akynes.

2.Reaction of alkylhalides.

3. Halogenation.

6 0
3 years ago
How many grams of salt are in 1 kilogram of seawater with average salinity? quizzlet?
Degger [83]
<span>35 grams The average salinity of seawater is 35 parts per thousand, so multiply the mass of seawater provided by 0.035 and you'll get the amount of salt (mostly sodium chloride) dissolved in it. So 1000 g * 0.035 = 35 g Therefore in 1 kilogram of seawater with average salinity, there is 35 grams of salt.</span>
5 0
3 years ago
What volume of Co2 (carbon (iv) oxide)
hram777 [196]

Answer:

2.1056L or 2105.6mL

Explanation:

We'll begin by calculating the number of mole in 10g of Na2CO3. This can be obtained as follow:

Molar mass of Na2CO3 = (23x2) + 12 + (16x3) = 106g/mol

Mass of Na2CO3 = 10g

Mole of Na2CO3 =.?

Mole = mass /molar mass

Mole of Na2CO3 = 10/106

Mole of Na2CO3 = 0.094 mole

Next, we shall determine the number of mole CO2 produced by the reaction of 0.094 mole of Na2CO3. This is illustrated below:

Na2CO3 + 2HCl —> 2NaCl + H2O + CO2

From the balanced equation above,

1 mole of Na2CO3 reacted to produce 1 mole of CO2.

Therefore, 0.094 mole of Na2CO3 will also react to 0.094 mole of CO2.

Next, we shall determine the volume occupied by 0.094 mole of CO2 at STP. This is illustrated below:

1 mole of a gas occupy 22.4L at STP. This implies that 1 mole CO2 occupies 22.4L at STP.

Now, if 1 mole of CO2 occupy 22.4L at STP, then, 0.094 mole of CO2 will occupy = 0.094 x 22.4 = 2.1056L

Therefore, the volume of CO2 produced is 2.1056L or 2105.6mL

7 0
3 years ago
IUPAC NAME FOR:<br>CH2(OH)-CH2-CH(C2H5)-OH
fgiga [73]

The IUPAC name for the organic compound CH2(OH)-CH2-CH(C2H5)-OH is Pentan-1,3-diol

This compound above belong to class of organic compound called the alkanols

<h3>What are organic compounds?</h3>

Organic compounds are compounds which contains carbon and hydrogen only.

Some few classes of organic compounds includes the following:

  • Alkanes
  • Alkenes
  • Alkynes
  • Alkanols
  • Alkanals
  • Alkanones
  • Esters
  • Ketones and other

So therefore, the IUPAC name for the organic compound is CH2(OH)-CH2-CH(C2H5)-OH is Pentan-1,3-diol

Learn more about organic compounds:

brainly.com/question/704297

#SPJ1

6 0
2 years ago
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