Answer:
The molarity of the sodium hydroxide solution is 0.0692 M
Explanation:
<u>Step 1: </u>Data given
Mass of H2C2O4 = 385 mg = 0.385 grams
volume = 250 mL = 0.250 L
Volume of NaOH = 123.7 mL = 0.1237 L
Molar mass H2C2O4 = 90.03 g/mol
<u>Step 2</u>: The balanced equation
2NaOH + H2C2O4 → Na2C2O4 + 2H2O
<u>Step 3:</u> Calculate moles H2C2O4
Moles H2C2O4 = mass H2C2O4 / molar mass H2C2O4
Moles H2C2O4 = 0.385 grams / 90.03 g/mol
Moles H2C2O4 = 0.00428 moles
<u>Step 4: </u>Calculate molarity of H2C2O4
Molarity H2C2O4 = moles / volume
Molarity H2C2O4 = 0.00428 moles / 0.250 L
Molarity H2C2O4 = 0.01712 M
<u>Step 5:</u> Calculate molarity of NaOH
2*Ca*Va = n*Cb*Vb
⇒ with Ca = Molarity of H2C2O4 = 0.01712 M
⇒ Va = volume of H2C2O4 = 0.250 L
⇒Cb = molarity of NaOH = TO BE DETERMINED
⇒ Vb = volume of NaOH = 0.1237 L
Cb = (2*0.01712*0.250)/0.1237
Cb = 0.0691 M
The molarity of the sodium hydroxide solution is 0.0692 M
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</h3><h3>Further explanation</h3>