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4 years ago

In a phospholipid the phosphate head is? and the acid tail is

1 answer:

6 0

The phosphate <u>head </u>is hydrophilic (faces outward in the lipid bilayer membrane), and the acid <u>tail </u>is lipophilic/hydrophobic (faces inward in the lipid bilayer membrane).

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What is the decreasing order of atomic size<br>F, Mg, Sr, P

lesya692 [45]

Answer:

Sr, Mg, P, F

Explanation:

The trend for decreasing radii size is up and to the right of the Periodic Table.

4 0

3 years ago

The chemical formula for the initial sample is mnso4·h2o and the chemical formula for the final sample is mnso4. use their molec

sammy [17]

The initial sample has a molecular formula of MnSO₄·H₂O. This molecule is a hydrate as it has a unit of water within its structure for every molecule of MnSO₄. This sample is being dehydrated to remove the water to give.

MnSO₄·H₂O → MnSO₄ + H₂O

MnSO₄·H₂O has a molecular mass of 169.02 g/mol. While MnSO₄ has a molecular mass of 151 g/mol. Water has a molecular mass of 18.02 g/mol. We now can use the ratio of the mass of water to the mass of the initial sample to determine the percentage of each component by mass.

% water by mass:

18.02/169.02 x 100% = 10.7% Water by mass.

% MnO₄ by mass:

151/169.02 x 100% = 89.3% MnSO₄ by mass.

Water makes up 10.7% of the initial mass of MnSO₄·H₂O.

4 0

3 years ago

A GFCI is an example of what kind of electrical safety device?

vichka [17]

Answer:

Circuit breaker.

Explanation:

3 0

3 years ago

Read 2 more answers

Which of the following 0.820 M solutions would have the greatest colligative effect?

eimsori [14]

Answer:

K3PO4

Explanation:

Recall that colligative properties depends on the number of particles present. The greater the number of particles present, the greater the degree of colligative properties of the solution. Let us look at each option individually;

SrCr2O7-------> Sr^2+ + Cr2O7^2- ( 2 particles)

C4H11N (not ionic in nature hence it can not dissociate into ions)

K3PO4-------> 3K^+ + PO4^3- (4 particles)

Rb2CO3-------> 2Rb^+ + CO3^2- (3 particles)

Hence K3PO4 has the greatest number of particles and will display the greatest colligative effect.

8 0

3 years ago

When hydrochloric acid is poured over potassium sulfide, 42.5 mL of hydrogen sulfide gas is produced at a pressure of 756 torr a

EastWind [94]

<h2>Answer:</h2> $0.1899grams$

<h2>Explanations:</h2>

The balanced chemical reaction between hydrochloric acid and potassium sulfide is as shown:

$K_2S+2HCl\to H_2S+2KCl$

Based on stoichiometry, we can see that 1 mole of potassium sulfide reacted to form 1 mole of hydrogen sulfide.

Get the mole of hydrogen sulfide gas (H2S) using the ideal gas equation expressed as:

$\begin{gathered} PV=\text{nRT} \\ n=\frac{PV}{RT} \end{gathered}$

P is the pressure of the gas (in atm) = 0.994737atm (756torr)

V is the volume of the gas = 42.5mL = 0.0425L

T is the temperature (in Kelvin) = 26 + 273 = 299K

R is the gas constant = 0.0821 L*atm/mole * K

Substitute these values into the formula as shown:

$\begin{gathered} n=\frac{0.994737\cancel{\text{atm}}\times0.0425\cancel{L}}{0.0821\frac{\cancel{L}\cdot\cancel{\text{atm}}}{\text{mole}\cdot\cancel{K}}\times299\cancel{K}} \\ n=\frac{0.994737\times0.0425}{0.0821\times299} \\ n=\frac{0.0422763225}{24.5479} \\ n=0.00172\text{moles} \end{gathered}$

Since the number of moles of hydrogen sulfide is 0.00172moles, the number of moles of potassium sulfide will also be 0.00172 moles (based on stoichiometry)

Get the mass of potassium sulfide that reacted using the formula:

$\text{Mass}=number\text{ of moles}\times molar\text{ mass}$

Number of moles of K2S = 0.00172 moles

Molar mass of K2S = 110.262 g/mol

Substitute into the formula for calculating the mass;

$\begin{gathered} \text{Mass}=0.00172\cancel{\text{moles}}\times\frac{110.262g}{\cancel{\text{mole}}} \\ \text{Mass}=0.1899\text{grams} \end{gathered}$

Therefore the mass of potassium sulfide that reacted (in grams) is approximately 0.1899grams

3 0

1 year ago