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sergeinik [125]

3 years ago

15

In a phospholipid the phosphate head is? and the acid tail is

1 answer:

Marina CMI [18]3 years ago

6 0

The phosphate <u>head </u>is hydrophilic (faces outward in the lipid bilayer membrane), and the acid <u>tail </u>is lipophilic/hydrophobic (faces inward in the lipid bilayer membrane).

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CHEM HELP PLZZZZ!!!!!

earnstyle [38]

Answer:

1. acid

2. neutral

3. acid

4. base

5. acid

6. base

7. neutral

8. acid

9. base

10. base

Explanation:

I'm not 100 percent positive about number three but the rest I believe are correct

3 0

2 years ago

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Which reaction should be used to convert propene into an alkyl halide?

skelet666 [1.2K]

Substitution that is it

4 0

3 years ago

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Diatomic oxygen has a molar mass 16 times that of diatomic hydrogen. The root-mean-square speed vrms for diatomic oxygen at 50∘C

trapecia [35]

Answer:(16)(2000)m/s=32000m/s

Explanation: A diatomic oxygen has a molar mass of 16

8 0

3 years ago

Oxidation of methane

Mandarinka [93]

<h2><em><u>ᎪꪀsωꫀᏒ</u></em></h2>

➪Methane (CH4) is oxidized with molecu- lar oxygen (O2) to carbon dioxide (CO2).

4 0

3 years ago

Air at 7S°F and14.6 though a cfm(cubic ft per minute) and the The flow rate is 48000 psia flows though a rectangular duct of Ix2

IgorLugansk [536]

Explanation:

The given data is as follows.

Air is at $75^{o}F$ and 14.6 psia.

$\varepsilon$ = 0.00015 ft, Flow rate, (Q) = 48000 $ft^{3}/m$

(a) Formula to calculate hydraulic radius $(r_{H})$ is as follows.

$r_{H} = \frac{\text{free flow area}}{\text{wet perimeter}}$

= $\frac{2 \times 1}{2(1) + 2(2)}$

= $\frac{1}{3}$ ft

Formula for equivalent diameter is as follows.

$D_{eq} = 4 \times r_{H}$

= $4 \times \frac{1}{3} ft$

= $\frac{4}{3}$ ft

(b) Formula for velocity floe is as follows.

Q = VA

V = $\frac{Q}{A}$

= $\frac{48000}{2 \times 1}$ ft/min

= 24000 ft/min

(c) Formula to calculate Reynold's number is as follows.

$R_{e}$ = $\frac{D \times V \times \rho}{\mu}$

= $\frac{\frac{4}{3} \times 24000 \times 0.0744}{0.0443}$ (as $\rho = 0.0744 lb/ft^{3}$ and $\mu$ = 0.0443 lb/ft. hr)

= 53742.66 hr/min

As 1 hr = 10 min. So, $53742.66 hr/min \times \frac{60 min}{1 hr}$

= 3224559.6

(d) Formula to calculate pressure drop $(\Delta P)$ is as follows.

$\frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}$

Putting the given values into the above formula as follows.

$\frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}$

= $\frac{4 \times 0.00015 \times 100 \times 0.0744 \times (24000)^{2}}{2 \times \frac{4}{3} \times {4}{3}}$

= 6.238 $lb/ft^{2}$

5 0

3 years ago