Answer:
0.54g of Cr
Explanation:
Current (I) = 10A
Time (t) = 100s
Molecular mass of Cr = 51.996 amu
Faraday's first law of electrolysis states that
The mass of the substance (m) of a given substance deposited at an electrode is directly proportional to the quantity of electricity or charge (Q) passed
m = nQ
M = mass of the substance
n = electrochemical constant
Q = charge passed through it
Q = IT
Q = (10 * 100) = 1000C
1 moles = molarmass = Faraday's constant (96500C)
Molar mass = Faraday's constant (96500C)
51.996 g = 96500C
How many grams will be liberated with 1000C
51.996g = 96500C
Xg = 1000C
X = (1000 * 51.996) / 96500
X = 51996 / 96500
X = 0.5388g = 0.54 g of Cr will be deposited
Explanation:
1: fluorine to form lithium fluoride
2:bcos covalent bond exists btw two non metals
3: bcos it is d combination of two or more elements nd elements r substances
4: for sbustances we hv flame test nd splint test
ionic compounds are held by strong electrostatic forces of attraction
Answer:
Well this has a good chance of being wrong but i wanna say,
When you change a physical property of something it doesn't affect the chemicals that make it up. Like Ice, you can freeze water to make ice. You change a physical property (state of matter) but it's chemical properties don't change because in the end it's still water.
However if you remove a chemical property from something you are changing what made the new substance with will also change the substance along with it.
That's just what I think though
Explanation:
Answer:
1597,5 gm AlCl3 decomposed
Explanation:
2AlCl3 --> 2Al + 3Al2 If you produce 15 moles of Al, how many grams of AlCl3 decomposed?
FIRST, you need to write down the the correct reaction. Your equation makes no sense
here is the correct question
2AlCl3 --> 2Al + 3Cl2 If you produce 15 moles of Al, how many grams of AlCl3 decomposed?
for every mole of Al produced, we decomposed a mole of AlCl3
so we produced 15 moles of Al, so we decomposed 15 moles of AlCl3
15 moles are 15 X 106.5 = 1597,5 gm AlCl3 decomposed
