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Nadya [2.5K]
3 years ago
13

An experiment is designed to test what color of light will activate a photoelectric cell the best. The photocell is set in a cir

cuit that "clicks" in response to current. The faster the current, the more clicks per minute. In this experiment, the number of clicks in one minute is recorded for each color of light shining on the photocell. To change the color of light, a different color of cellophane is placed over the same flashlight and the flashlight is then located a specific distance from the photocell.
In the above experiment, which factor is the independent variable?
Chemistry
2 answers:
ella [17]3 years ago
7 0

Answer;the color of light shining on the photocell

Explanation:

nikklg [1K]3 years ago
3 0

Answer: the color of light shining on the photocell.

Explanation:

1) In an experiment there are two kind of variables: independent variables and dependent variables.

2) The independent variable is the one that can be changed or manipulated. This is done because you want to learn how the changes in this variable may explain or are related to other variable (the dependent variable).

In the description of the experiment, the color of the light is being changed, by placing different color of cellophanes ove the same flashlight.

This is how, keeping the control over other possible variables (the flashlight kind and its distance from the photocell, for example) the experimenter manages to change one only variable: the color of light.

3) On the other hand, the dependent variable, is the variable that is being explained. You do not manipulate the dependent variable directly but you want to learn to what extent this dependent variable is determined by, explained by, predicted by, or simply related to, the independent variable.

In conclusion, the independent variable is the color of light.

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How many moles of H2SO4 are needed to completely neutralize 0.0164 mol KOH
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0.0082 You have to equal out the amount of concentration with the unknown
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3 years ago
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Where did water become gas?
ASHA 777 [7]
Answer: Water becomes gas at D-E.

Explanation:
In the flat line D-E water is absorbing energy to become gas, and when the water is completely gas, the temperature will increase again therefore the line will rise up.
8 0
2 years ago
Calculate the volume in liters of a 0.00231M copper(II) fluoride solution that contains 175.g of copper(II) fluoride CuF2. Be su
Free_Kalibri [48]

Answer:

Volume = 746 L

Explanation:

Given that:- Mass of copper(II) fluoride = 175 g

Molar mass of copper(II) fluoride = 101.543 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{175\ g}{101.543\ g/mol}

Moles_{copper(II)\ fluoride}= 1.7234\ mol

Also,

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

So,,

Volume =\frac{Moles\ of\ solute}{Molarity}

Given, Molarity = 0.00231 M

So,

Volume =\frac{1.7234}{0.00231}\ L

<u>Volume = 746 L</u>

7 0
2 years ago
What is the molar concentration of the acid if 35.18 mL of hydrochloric acid was required to neutralize 0.745 g of ALUMINUM hydr
Makovka662 [10]

The mass number of aluminium hydroxide is 78 thus, the number of moles in 0.745 g is:

no. of moles= mass/ RFM

= 0.745/78

=0.00955moles

Therefore the 0.00955 moles should be in the 35.18 ml

therefore 1000ml of the solution will have:

(0.00955ml×1000ml)/35.18

=0.2715moles

The  solution will be 0.27M hydrochloric acid  

3 0
2 years ago
Question 3 0
Tanya [424]

Answer:

Option D. KBr < KCl < NaCl

Explanation:

We'll begin by calculating the number of mole of each sample.

This can be obtained as follow:

For NaCl:

Mass = 1 g

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mole of NaCl =?

Mole = mass /Molar mass

Mole of NaCl = 1/58.5

Mole of NaCl = 0.0171 mole

For Kbr:

Mass = 1 g

Molar mass of KBr = 39 + 80 = 119 g/mol

Mole of KBr =?

Mole = mass /Molar mass

Mole of KBr = 1/119

Mole of KBr = 0.0084 mole

For KCl:

Mass = 1 g

Molar mass of KCl = 39 + 35.5 = 74.5 g/mol

Mole of KCl =?

Mole = mass /Molar mass

Mole of KCl = 1/74.5

Mole of KCl = 0.0134 mole

Summary

Sample >>>>>>>> Number of mole

NaCl >>>>>>>>>> 0.0171

KBr >>>>>>>>>>> 0.0084

KCl >>>>>>>>>>> 0.0134

Arranging the number of mole of the sampl in increasing order, we have:

KBr < KCl < NaCl

5 0
3 years ago
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