Question

Dos cargas puntuales (q1 y q2 ) se atraen inicialmente entre sí con una fuerza de 550 N , si la separación entre ellas es de 90 cm. La carga q1 = +55 µC ¿Cuál es el valor de la carga q2?

Answer 1

Answer:

q2 = 9.02*10^{-4}C

Explanation:

To find the value of the other charge you use the Coulomb's law:

$F=k\frac{q_1q_2}{r^2}$

k: Coulomb's constant = 8.98*10^{9}Nm^2/C^2

q1: charge 1 = 55*10^{-6}C

r: distance between charges = 90cm = 0.9m

F: electric force = 550N

By doing q2 the subject of the formula and replacing you obtain:

$q_2=\frac{r^2F}{kq_1}=\frac{(0.9m)^2(550N)}{(8.98*10^9Nm^2/C^2)(55*10^{-6}C)}=9.02*10^{-4}C$

hence, the value of the other charge q2 is 9.02*10^{-4}C