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zalisa [80]
3 years ago
13

Karla Ayala pulls a sled on an icy road (dangerous!). Because of Karla's pull, the tension force is 151 N, and the rope makes a

20.0° with the horizontal. If the 7.0-kg sled is pulled across 10.0 meters, what is the work done by Karla?
Physics
1 answer:
skelet666 [1.2K]3 years ago
6 0

Answer:

W = 1418.9 J = 1.418 KJ

Explanation:

In order to find the work done by the pull force applied by Karla, we need to can use the formula of work done. This formula tells us that work done on a body is the product of the distance covered by the object with the component of force applied in the direction of that displacement:

W = F.d

W = Fd Cosθ

where,

W = Work Done = ?

F = Force = 151 N

d = distance covered = 10 m

θ = Angle with horizontal = 20°

Therefore,

W = (151 N)(10 m) Cos 20°

<u>W = 1418.9 J = 1.418 KJ</u>

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The correct answer is
<span>force per unit charge.

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</span>E= \frac{F}{q}
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3 years ago
I need help on a it all please
Akimi4 [234]

your answer is the letter (b)


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16x^2y^2-25a^2b^2<br>factorize the expression​
SIZIF [17.4K]

Answer:

(4xy+5ab)(4xy-5ab)

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So, this factorized is:

(4xy+5ab)(4xy-5ab)

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2 years ago
Tom is sitting facing forward in the train as it is getting ready to leave the station. He puts a smooth ball on the train floor
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According to Newton's first law of motion, what happens to the ball is  the ball rolls backward.

<h3>What is the first law?</h3>

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2 years ago
On a popular amusement park ride, the riders stand along the inside wall of a large cylinder with a diameter of 8.27 m. The cyli
____ [38]

Answer:

Explanation:

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ω = 0.66 rev/sec = (0.66 rev/sec)*(2π rad/1 rev) = 4.1469 rad/s

We can apply the equation

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then we have

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Returning to the equation <em>I</em>

<em />

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Finally

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