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ki77a [65]
3 years ago
8

A woman holds a book by placing it between her hands such that she presses at right angles to the front and back covers. The boo

k has a mass of m = 1.3 kg and the coefficient of static friction between her hand and the book is μs = 0.69. What is the weight of the book in Newton?

Physics
1 answer:
In-s [12.5K]3 years ago
7 0

Answer:

Explanation:

In order to solve this problem we need to make a free body diagram of the book and the forces that interact on it. In the picture below you can see the free body diagram with these forces.

The person holding the book is compressing it with his hands, thus exerting a couple of forces of equal magnitude and opposite direction with value F.

Now the key to solving this problem is to analyze the equilibrium condition (Newton's third law) on the x & y axes.

To find the weight of the book we simply multiply the mass of the book by gravity.

W = m*g

W = 1.3[kg] * 9.81[m/s^2]

W = 12.75 [N]

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Answer:

2406 miles

Explanation:

Let A be the starting position, B the junction position and C the final position after flying the 3.5 hrs. Also, let b be the distance from the starting point:

\angle ABC =(180-10) \textdegree=170\textdegree

#Distance traveled in 1.5hrs is;

c=690x1.5\\=1035mi

#Distance traveled in next two hrs:

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#Now using the Cosine Rule:

b^2=a^2+c^2-2ab\cos B\\\\=1380^2+1035^2-2(1380)(1035)cos170\textdegree\\\\b^2=5788.83\\\\b\approx 2406.00 \ mi

Hence, the pilot is 2406 miles from her starting position.

4 0
3 years ago
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If not then A but I'm positive its B

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what if l was standing and all of continent are coming together and becomes pangea.What will happen???
azamat

Answer:

not really

Explanation:

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