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2 years ago

Temperature (°C)

Chemistry

1 answer:

Andreyy892 years ago

5 0

The answer is the solution saturated than more dissolved with is C

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Which of these are formed when

makvit [3.9K]

Option d lo siento si es incorrecto

7 0

3 years ago

The calorimeter pictured below shows the final temperature after calcium chloride was added to water. (The initial temperature w

max2010maxim [7]

It’s probably D or c

3 0

3 years ago

Read 2 more answers

If equal volumes of 0.1 M HCl and 0.2 M TRIS (base form) are mixed together. The pKa of TRIS is 8.30. Which of the following sta

blondinia [14]

Answer:

option D is correct

D. This solution is a good buffer.

Explanation:

TRIS (HOCH $_{2}$ ) $_{3}$ CNH $_{2}$

if TRIS is react with HCL it will form salt

(HOCH $_{2}$ ) $_{3}$ CNH $_{2}$ + HCL ⇆ (HOCH $_{2}$ ) $_{3}$ NH $_{3}$ CL

Let the reference volume is 100

Mole of TRIS is = 100 × 0.2 = 20

Mole of HCL is = 100 × 0.1 = 10

In the reaction all of the HCL will Consumed,10 moles of the salt will form

and 10 mole of TRIS will left

hence , Final product will be salt +TRIS(9 base)

H = Pk $_{a}$ + log (base/ acid)

8.3 + log(10/10)

8.3

6 0

3 years ago

Use the IUPAC nomenclature rules to give the name for Mg(ClO4)2

Makovka662 [10]

Answer:

The answer to your question is Magnesium Perchlorate

Explanation:

IUPAC Rules to name ternary salts of chlorine

1.- Ternary salts use prefixes and suffixes it depends on the number of oxygens they have.

Example

Metal + Chlorine + 1 oxygen = Name of the metal + hipo chlor + ite

Metal + Chlorine + 2 oxygens = Name of the metal + chlor + ite

Metal + Chlorine + 3 oxygens = Name of the metal + chlor + ate

Metal + Chlorine + 4 oxygens = Name of the metal + per + chlor + ate

For this compound the name is Magnesium Perchlorate.

6 0

3 years ago

Determine ΔH for the reaction CaCO3 → CaO + CO2 given these data: 2 Ca + 2 C + 3 O2 → 2 CaCO3 ΔH = −2,414 kJ C + O2 → CO2 ΔH = −

kicyunya [14]

Answer:

The ΔH for the reaction is -456.5 KJ

Explanation:

Here we want to determine ΔH for the reaction;

Mathematically;

ΔH = ΔH(product) - ΔH(reactant)

In the case of the first reaction;

ΔH = ΔH(CaO) + ΔH(CO2) - ΔH(CaCO3) ...........................(*)

From the other reactions, we can get the respective ΔH for the individual molecule in the reaction

In second reaction;

Kindly note that for elements, molecule of gases, ΔH = 0

What this means is that throughout the solution;

ΔH(Ca) = 0 KJ

ΔH(O2) = 0 KJ

ΔH(C) = 0 KJ

Thus, in writing the equation for the subsequent chemical reactions, we shall need to write and equate the overall ΔH for the reaction to that of the product alone

So in the second reaction

ΔH = 2ΔH(CaCO3)

Thus;

-2414/2 = ΔH(CaCO3)

ΔH(CaCO3) = -1,207 KJ

Moving to the third reaction, we have;

ΔH = ΔH(CO2)

Hence ΔH(CO2) = -393.5 KJ

For the last reaction;

ΔH = ΔH(CaO)

Hence ΔH(CaO) = -1270 KJ

Going back to equation *

ΔH = ΔH(CaO) + ΔH(CO2) - ΔH(CaCO3)

Using the values of the ΔH of the respective molecules given above,

ΔH = -1270 + (-393.5) - (-1207)

ΔH = -456.5 KJ

8 0

3 years ago