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likoan [24]
3 years ago
8

Two football players collide head-on in midair while trying to catch a thrown football. The first player is 98.5 kg and has an i

nitial velocity of 6.05 m/s, while the second player is 119 kg and has an initial velocity of −3.50 m/s. What is their velocity (in m/s) just after impact if they cling together? (Indicate the direction with the sign of your answer.)
Physics
1 answer:
romanna [79]3 years ago
7 0

Answer:

v_f=0.825m/s

Explanation:

We must use conservation of linear momentum before and after the collision, p_i=p_f

Before the collision we have:

p_i=p_1+p_2=m_1v_1+m_2v_2

where these are the masses are initial velocities of both players.

After the collision we have:

p_f=(m_1+m_2)v_f

since they clong together, acting as one body.

This means we have:

m_1v_1+m_2v_2=(m_1+m_2)v_f

Or:

v_f=\frac{m_1v_1+m_2v_2}{m_1+m_2}

Which for our values is:

v_f=\frac{(98.5kg)(6.05m/s)+(119kg)(-3.5m/s)}{(98.5kg)+(119kg)}=0.825m/s

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