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pav-90 [236]
2 years ago
6

4. A 180 kg sumo wrestler on roller skates, rolling at 5 m/s to the left, collides elastically with

Physics
1 answer:
Goryan [66]2 years ago
4 0

Answer:

m1u1+m2u2=m1v1+m2v2

Explanation:

m1=180

m2=215

u1=5

u2=3.5

v1=2

v2=?

use the above formula

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ikadub [295]

\sf \huge \purple{ Question : -  }

Initial velocity of a car is 36 km/h . Find the distance after min, if it goes with acceleration 2 m/s².

\sf \huge \color {gold}{ AnSwer :- }

Initial velocity, u = 36 km/h

\sf u = 36 \times  \dfrac{5}{18}  {ms}^{ - 1}  = 10 {ms}^{ - 1}

Time, t = 1min

  • t = 60s

Acceleration, a = 2m/s²

Apply 2nd equation of motion

\longrightarrow \sf s = ut +  \dfrac{1}{2} at ^{2}  \\  \\  \longrightarrow \sf s =(10)(60) +  \frac{1}{2} (2)(60) {}^{2}  \\  \\  \longrightarrow \sf s =600 + 3600   \\  \\  \longrightarrow \sf  \blue{ s =4200m}  \:  \: \large \blue \star

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The human heart is a powerful and extremely reliable pump. Each day it takes in and discharges about 7500 L of blood. Assume tha
gregori [183]

The answers are:

a) Work=125,923.61J

b) Power=1.46watt

Why?

It seems that you forgot to write the questions of the problem, however, in order to help you, I will try to complete it.

The questions are:

a) How much work does the heart do in a day?

b) What is its power output in watts?

So, solving we have:

We need to convert from liter to cubic meters in order to use the given information, so:

1L=0.001m^{3}\\\\7500L*\frac{0.001m^{3} }{1L}=7.5m^{3}

Also, we need to find the mass given the density of the blood.

1050}\frac{kg}{m^{3}}*7.5m^{3}=7875kg

Now, calculating how much work does the heart do in a day, we have:

Work=Fd=mgh\\\\Work=7875kg*9.81\frac{m}{s^{2}}*1.63m=125,923.61J

Then, calculating what is the power output and its horsepower, we have:

Power=\frac{Work}{time}\\\\Power=\frac{125,923.61J}{86,400s}=1.46watt

Have a nice day!

7 0
3 years ago
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