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2 years ago

4. A 180 kg sumo wrestler on roller skates, rolling at 5 m/s to the left, collides elastically with

Physics

1 answer:

Goryan [66]2 years ago

4 0

Answer:

m1u1+m2u2=m1v1+m2v2

Explanation:

m1=180

m2=215

u1=5

u2=3.5

v1=2

v2=?

use the above formula

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$\sf \huge \purple{ Question : - }$

Initial velocity of a car is 36 km/h . Find the distance after min, if it goes with acceleration 2 m/s².

$\sf \huge \color {gold}{ AnSwer :- }$

Initial velocity, u = 36 km/h

$\sf u = 36 \times \dfrac{5}{18} {ms}^{ - 1} = 10 {ms}^{ - 1}$

Time, t = 1min

t = 60s

Acceleration, a = 2m/s²

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$\longrightarrow \sf s = ut + \dfrac{1}{2} at ^{2} \\ \\ \longrightarrow \sf s =(10)(60) + \frac{1}{2} (2)(60) {}^{2} \\ \\ \longrightarrow \sf s =600 + 3600 \\ \\ \longrightarrow \sf \blue{ s =4200m} \: \: \large \blue \star$

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The human heart is a powerful and extremely reliable pump. Each day it takes in and discharges about 7500 L of blood. Assume tha

gregori [183]

The answers are:

a) $Work=125,923.61J$

b) $Power=1.46watt$

Why?

It seems that you forgot to write the questions of the problem, however, in order to help you, I will try to complete it.

The questions are:

a) How much work does the heart do in a day?

b) What is its power output in watts?

So, solving we have:

We need to convert from liter to cubic meters in order to use the given information, so:

$1L=0.001m^{3}\\\\7500L*\frac{0.001m^{3} }{1L}=7.5m^{3}$

Also, we need to find the mass given the density of the blood.

$1050}\frac{kg}{m^{3}}*7.5m^{3}=7875kg$

Now, calculating how much work does the heart do in a day, we have:

$Work=Fd=mgh\\\\Work=7875kg*9.81\frac{m}{s^{2}}*1.63m=125,923.61J$

Then, calculating what is the power output and its horsepower, we have:

$Power=\frac{Work}{time}\\\\Power=\frac{125,923.61J}{86,400s}=1.46watt$

Have a nice day!

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