A) 1.55
The speed of light in a medium is given by:

where
is the speed of light in a vacuum
n is the refractive index of the material
In this problem, the speed of light in quartz is

So we can re-arrange the previous formula to find n, the index of refraction of quartz:

B) 550.3 nm
The relationship between the wavelength of the light in air and in quartz is

where
is the wavelenght in quartz
is the wavelength in air
n is the refractive index
For the light in this problem, we have

Therefore, we can re-arrange the equation to find
, the wavelength in air:

Answer:

Explanation:
We use the kinematics equation to solve this question:

because the ball is dropped
the acceleration is the gravity, negative because it points downwards
initial height
final height
So:


The direction of electric field by the charge in and on the metal block will be along the direction line 5 as given in question.
<h3>
How to determine electric field direction in a metal block?</h3>
The charge always remain on outer surface of metal and inside the metal block, the net electric field is zero. But due to dipole there is an electric field at the center of metal block i.e. at point R along direction line 1.
Now, to make make the net electric field zero at center, the electric field by the charge in and on the metal block must be equal in magnitude to that of electric field due to dipole at point R and in opposite direction to that of the net electric field at at R due to dipole.
The electric field by the charge in and on the metal block will be making 180° angle to the electric field due to dipole at point R.
Hence the direction of electric field by the charge in and on the metal block will be along the direction line 5 as given in question.
To know more about electric field, click on brainly.com/question/11509296
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Answer:
d= 100m
Explanation:
Cheetah kinematic
The cheetah moves with uniformly accelerated movement, and the formulas that describe this movement are:
d= v₀*t + (1/2)*a*t² Formula (1)
vf²=v₀²+2*a*d Formula (2)
vf=v₀+a*t Formula (3)
Where:
d:distance in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
a: acceleration in m/s²
t: time in seconds (s)
Known Data
v₀ =0
a = 4.5 m/s²
vf= 30 m/s.
Problem development
We apply the formula (2) that has known data to calculate the distance :
vf²=v₀²+2*a*d
(30)²= 0 + 2* 4.5* d

d= 100m