Answer:
ion channel
Explanation:
discussion of ion channel structure and function, followed by the classical description of the action potential and the ... Resistance and Conductance depend on the size and shape of the object that you are passing ... Intracellular and extracellular ion concentrations must ... applied to essentially any cell type.
Answer:
displacement (x) = 0.003798 meters
Explanation:
from the fact that the string is hung vertically we can deduce that:
Total force acting on the mass = Fs (by spring) + Fg (by gravity)
<em>where</em>
Fs = k*x , x is the displacement..
Fg = m*g
then:
Ftot = m*a, <em>but a = 0 m/(s^2) because the mass becames stationary.</em>
Ftot = 0
Fs + Fg = 0
<em>by direction, take down as negative.</em>
Fs - Fg = 0
k*x = m*g
x = m*g/k = [(0.400)(9.8)]/(10.32)
= 0.3798 meters
Answer:
the equilibrium constant is equal to 1 (i.e., the reactant and product concentrations are always equal).
Explanation:
ΔG is a symbol related to Gibbs free energy, which is a physical quantity related to thermodynamics. ΔG refers to the difference between the change in enthalpy (and sometimes entropy) and the temperature of a chemical reaction.
Gibbs free energy is very useful for measuring the work done between the reactants in a reaction. It is calculated using the formula: ΔG = change in enthalpy - (temperature x change in entropy).
The ΔG of a reaction would have a minimum value (zero), if the equilibrium constant is equal to 1 (that is, the concentrations of the reagent and the product are always equal).
This type of energy is called non mechanical energy so the answer is C
Answer:
f = v / 4L
the frequency of the instruments is reduced by the decrease in the speed of the wave with the temperature.
Explanation:
In wind instruments the wave speed must meet
v = λ f
λ = v / f
from v is the speed of sound that depends on the temperature
v = v₀
where I saw the speed of sound at 0ºC v₀ = 331 m/s the temperature is in degrees centigrade, we can take the degrees Fahrenheit to centigrade with the relation
(F -32) 5/9 = C
76ºF = 24.4ºC
45ºF = 7.2ºC
With this relationship we can see that the speed of sound is significantly reduced when leaving the house to the outside
at T₁ = 24ºC v₁ = 342.9 m / s
at T₂ = 7ºC v₂ = 339.7 m / s
To satisfy this speed the wavelength of the sound must be reduced, so the resonant frequencies change
λ / 4 = L
λ= 4L
v / f = 4L
f = v / 4L
Therefore, the frequency of the instruments is reduced by the decrease in the speed of the wave with the temperature.