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Usimov [2.4K]
3 years ago
11

What happens inside an empty tank when it is filled with air?

Physics
2 answers:
worty [1.4K]3 years ago
8 0

Answer:

pressure is created at the wall's surface

Explanation:

When air is filled in an empty tank, air molecules try to spread through out the tank. The gas molecules  has random and continues motion due to which they possess kinetic energy. Due to this energy air molecules continuously strike with the wall of the tank and apply force  on the wall of  tank due to which reaction force is applied on air  molecule In this way pressure is created on tanker's walls and it  becomes hot.

kobusy [5.1K]3 years ago
6 0

Answer:

An Empty Tank Is Slowly Filled With Air. Water Is Then Added To The Tank, Decreasing The Volume For The Air In The Tank. The Temperature Remains Constant

Explanation:

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how did we discover how to brake the sound barior and why did we not go as fast as the speed of light
quester [9]

The problem of the "sound barrier" has to do with moving through
air, and the things the air does when you try to push it out of the
way faster than the speed of sound.  Moving through air faster
than sound was an engineering and technological problem, not
a scientific one.

Concerning light, that's about 874 thousand times faster. 
See the problem ?

4 0
3 years ago
What is the impulse of a 1700 kg truck traveling at 22.5 m/s?
andrew-mc [135]
Impulse is just the product of mass and speed!

I = 1700 * 22.5  = 38,250 kg m/s

It does not have any special name for its units :(
3 0
3 years ago
The near point of a person's eye is 71.4 cm. To see objects clearly at a distance of 24.0 cm, what should be the focal length an
yuradex [85]

Answer:

The focal length of the appropriate corrective lens is 35.71 cm.

The power of the appropriate corrective lens is 0.028 D.

Explanation:

The expression for the lens formula is as follows;

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

Here, f is the focal length, u is the object distance and v is the image distance.

It is given in the problem that the given lens is corrective lens. Then, it will form an upright and virtual image at the near point of person's eye. The near point of a person's eye is 71.4 cm. To see objects clearly at a distance of 24.0 cm, the corrective lens is used.

Put v= -71.4 cm and u= 24.0 cm in the above expression.

\frac{1}{f}=\frac{1}{24}+\frac{1}{-71.4}

\frac{1}{f}=0.028

f= 35.71 cm

Therefore, the focal length of the corrective lens is 35.71 cm.

The expression for the power of the lens is as follows;

p=\frac{1}{f}

Here, p is the power of the lens.

Put f= 35.71 cm.

p=\frac{1}{35.71}

p=0.028 D

Therefore, the power of the corrective lens is 0.028 D.

3 0
3 years ago
A light bulb does 100 joules of work in 2.5 seconds. how much work power dos it have
Lesechka [4]
100/2.5 because power=energy/time
5 0
3 years ago
Two long, straight wires, one above the other, are seperated by a distance 2a2a and are parallel to the x−axisx−axis. Let the +y
kompoz [17]

Answer:

note:

<u>solution is attached in word form due to error in mathematical equation. furthermore i also attach Screenshot of solution in word due to different version of MS Office please find the attachment</u>

Download docx
3 0
3 years ago
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