Answer:
1.2044 × 10^24 oxygen atoms
Explanation:
To convert from moles to atoms, simply multiply the number of moles by Avogadro's number, 6.022 × 10^23
2 × 6.022 × 10^23
=1.2044 × 10^24
its 0.163 g
From the total pressure and the vapour pressure of water we can calculate the partial pressure of O2
PO 2 =P t −P H 2 O
= 760 − 22.4
= 737.6 mmHg
From the ideal gas equation we write.
W= RT/PVM = (0.0821Latm/Kmol)(273+24)K(0.974atm)(0.128L)(32.0g/mol/) =0.163g
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b competition .
hope it helps u
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