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3 years ago

An independent variable is....

Chemistry

1 answer:

Irina18 [472]3 years ago

5 0

Answer:

B - What we change

Explanation:

Dependent Variable - What we measure

Control Variable - what stays the same

Conclusion - what we conclude

Hope this can Help!

:D

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Some thermodynamic properties of ethanol are listed in the table. Thermodynamic Properties Property Value c (solid) 0.5 J/g °C c

alexira [117]

<h2>Answer </h2>

Option C - 320J

Explanation

Since ethanol solid at −120 °C and is only cooling down (it won’t change states) . The amount of Thermodynamic properties values c is given in form of solid, liquid and gas. Amount of energy released is calculated below.

Formula,

= change in temperature x specific heat capacity for solid ethanol x 40

=> 0.5 x 16x 40 = 320J

Therefore, the 320J of heat is released when 40.0g of ethanol cools.

4 0

3 years ago

How many phases are in a homogeneous mixture??

Mars2501 [29]

Technically there is only one phase unless you account for a solution where you have a pure liquid with something dissolved in it. Unless you count aqueous as a phase which is just dissolved. Since you are in high school the answer you are looking for is one.

7 0

3 years ago

Read 2 more answers

Represent the decomposition of aluminum oxide using the same number of atoms of molecules as are

pantera1 [17]

Answer:

Decomposition of aluminium oxide forms aluminium atoms and oxygen atoms.

Explanation:

Decomposition reaction:

When a single compound break down into two or more simpler products.

For example "AB" reactant undergoes decomposition to form "A" and "B" products.

The chemical reaction is as follows.

$AB\rightarrow A+B$

The given compound is aluminium oxide.

The decomposition reaction of aluminium oxide is a follows.

$Al_{2}O_{3}\rightarrow Al+O_{2}$

The balanced equation is as follows.

$2Al_{2}O_{3}\rightarrow 4Al+3O_{2}$

Therefore, Decomposition of aluminium oxide forms aluminium atoms and oxygen atoms.

4 0

3 years ago

A. 20 moles of NH3 are needed to produce how many moles of H2O?

tiny-mole [99]

a. 30 moles of H₂O

b. 2.33 moles of N₂

<h3>Further explanation</h3>

Given

a. 20 moles of NH₃

b. 3.5 moles of O₂

Required

a. moles of H₂O

b. moles of N₂

Solution

Reaction

4NH₃+3O₂⇒2N₂+6H₂O

a. From the equation, mol ratio NH₃ : H₂O = 4 : 6, so mol H₂O :

=6/4 x mol NH₃

= 6/4 x 20 moles

= 30 moles

b. From the equation, mol ratio N₂ : O₂ = 2 : 3, so mol N₂ :

=2/3 x mol O₂

= 2/3 x 3.5 moles

= 2.33 moles

7 0

2 years ago

Un móvil se mueve con movimiento acelerado. En los segundo 2 y 3 los espacios recorridos son 90 y 120 m, Calcula la velocidad in

faust18 [17]

Answer:

La velocidad inicial es 55 $\frac{m}{s}$ y su aceleración es -10 $\frac{m}{s^{2} }$

Explanation:

Un movimiento es rectilíneo uniformemente variado, cuando la trayectoria del móvil es una línea recta y su velocidad varia la misma cantidad en cada unidad de tiempo . Dicho de otra manera, este movimiento se caracteriza por una trayectoria que es una línea recta y la velocidad cambia su módulo de manera uniforme: aumenta o disminuye en la misma cantidad por cada unidad de tiempo. Y la aceleración es constante y no nula (diferente de cero).

En este caso la posición del objeto esta dada por la expresión:

$x=x0+v0*t+\frac{1}{2} *a*t^{2}$

donde x es la posición del cuerpo en un instante dado, x0 la posición en el instante inicial, v0 la velocidad inicial y a la aceleración.

En este caso, por un lado podes considerar:

x= 90 m
x0= 0 m
v0= ?
t= 2
a= ?

Reemplazando obtenes:

$90=v0*2+\frac{1}{2} *a*2^{2}$

$90=v0*2+\frac{1}{2} *a*4$

$90=v0*2+2*a$

Y por otro lado tenes:

x= 120 m
x0= 0
v0= ?
t= 3
a= ?

Reemplazando obtenes:

$120=v0*3+\frac{1}{2} *a*3^{2}$

$120=v0*3+\frac{1}{2} *a*9$

$120=v0*3+\frac{9}{2} *a$

Por lo que tenes el siguiente sistema de ecuaciones:

$\left \{ {{2*v0+2*a=90} \atop {3*v0+\frac{9}{2} *a=120}} \right.$

Resolviendo por el método de sustitución, que consiste en aislar en una ecuación una de las dos incógnitas para sustituirla en la otra ecuación, obtenes:

Despejando v0 de la primera ecuación:

$v0= \frac{90-2*a}{2}$