Structure 1 is satisfying octet rule because each atom surrounded by 8 electrons:
The valance electron for oxygen is 6, for sulfur is 6, but for hydrogen is 1. Therefore, the molecule has <span>valance electrons. Sulfur is bonded with 4 oxygen atoms, 4 single bonds, whereas 2 hydrogen atoms are bonded with 2 oxygen atoms.
But the actual structure is 2 but it violates octet rule since S is surrounded in this case with 12 electrons
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<h3>To find the empirical formula you need the relative atomic mass of each element!</h3>
N = 14
H = 1
S = 32.1
<h3>You can simply change the percentages into full grams</h3>
N = 12.20
H = 6.06
S = 48.45
<h3>Then you use this to find the Number of moles = amount in grams / atomic mass</h3>
N = 12.20 ÷ 14 = 0.8714
H = 6.06 ÷ 1 = 6.06
S = 48.45 ÷ 32.1 = 1.541
<h3>Then divide each number of moles by the smallest value:</h3>
N = 0.8714 ÷ 0.8714 = 1
H = 6.06 ÷ 0.8714 = 6.9 ≈ 7
S = 1.541 ÷ 0.8714 = 1.76 ≈ 2
So that means that there are 1 Nitrogen, 7 hydrogen, and 2 sulfur. This means the empirical formula would be:
NH₇S₂
Hope this helps!
C) can give up electrons more readily than others.
Answer:
Explanation:
First thing is we have assume all the percents are grams so we have
68.279g C, 6.2760g H, 3.7898g N, and 21.656g O
Now convert each gram to moles by dividing the the molar mass of each element
68.279g/12.01g= 5.685 moles of C
6.2760g/1.01g= 6.214 moles of H
3.7898g N/14.01g= 0.271 moles of N
21.656g O/ 16.00g= 1.354 moles of O
Now to find the lowest ratios divide all the moles by the smallest number of moles you found, in our case, the smallest moles is 0.271 moles of N so divide everything by that....
5.685 moles/0.271 moles ------> ~21 C
6.214 moles/0.271 moles --------> ~23 H
0.271 moles / 0.271 moles ---------> 1 N
1.354 moles/ 0.271 moles ----------> ~5 O
So the empirical formula is C21H23NO5
Answer:
I wish I spoke this languge.
Explanation:
