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pantera1 [17]
3 years ago
13

PHYSICS QUESTION, WILL MARK BRAINLIEST !!! A construction truck collides with the back of a subcompact car. Which one has the la

rger change of velocity during the collision?
The huge truck has a larger change in velocity
They have the same change of velocity
Neither one changes its velocity
The small car has a larger change in velocity.

Please explain the answer.
Physics
2 answers:
ozzi3 years ago
8 0

Answer:

the small car has a larger change in velocity

Explanation:

it has a larger change in velocity because it is small compared to the big truck that hit the car.

Sonbull [250]3 years ago
4 0

Answer: The small car has a larger change in velocity.

Explanation:

The largest change of velocity will be in the smallest mass car, this happens because in the collision the change is in the kinetic energy; k = (1/2)m*v^2

where m is the mass and v is the velocity

so for a fixed change of kinetic energy k (that depends on the collision), if m is big, the change in v must be small, and if m decreases, v must increase.

from this, we can see that the vehicle with a smaller mass will be the biggest change in the velocity.

The correct option is:

The small car has a larger change in velocity.

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A 70kg car drives through a curve with radius 50m. What is the minimum angle the road should be tilted to keep the car on the ro
worty [1.4K]

when car moves along a circular path then centripetal force for taking turn will be provided by the component of normal force

Let the road is tilted by some angle

so force equations are given as

F_n cos\theta = mg

F_n sin\theta = \frac{mv^2}{R}

now divide two equations

tan\theta = \frac{v^2}{Rg}

now as it is given to us that

v = 80 km/h

v = 80* \frac{5}{18} = 22.2 m/s

R = 50 m

now we have

tan\theta = \frac{22.2^2}{50*9.8}

tan\theta = 1

\theta = tan^{-1}1

\theta = 45^0

so it is inclined at an angle of 45 degree

8 0
3 years ago
According to this graph, which statement describes how the amount of iron changes over time in the reaction
VashaNatasha [74]
The graph shows the production of Fe, from the graph that it increases rapidly and then slowly increases.<span>The answer is a! (:
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5 0
4 years ago
What is the potential energy of a 25 kg bicycle resting at the top of a hill 3 m high (formula:pe=mgh)
yKpoI14uk [10]

The potential energy of a 25 kg bicycle resting at the top of a hill 3 m high will be 735.75 J.

<h3>What is potential energy?</h3>

The potential energy is due to the virtue of the position and the height. The unit for the potential energy is the joule.

The potential energy is mainly depending upon the height of the object. when the cyclist is at the highest position, the height is maximum. Therefore, the potential energy is also maximum.

The potential energy is found as;

PE=mgh

PE=25 kg× 9.81 m/s² ×3 m

PE= 735.75 J.

Hence, the potential energy of a 25 kg bicycle resting at the top of a hill 3 m high will be 735.75 J.

To learn more about the potential energy, refer to the link;

brainly.com/question/24284560

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5 0
2 years ago
If an ocean wave passes a stationary point every 5 s and has a velocity of 10 m/s, what is the wavelength of the wave
Rainbow [258]

Answer:

As Per Provided Information

Velocity of wave v is 10m/s

These ocean wave passes a stationary point every 5 s ( It's time period)

First we calculate the frequency of ocean wave .

<u>Using</u><u> Formulae</u>

\blue{\boxed{\bf \:  \nu =  \cfrac{1}{v}}}

here

v is the velocity of wave .

\sf\longrightarrow \nu \:  =  \cfrac{1}{10}  \\  \\ \\  \sf\longrightarrow \nu \:  = 0.1Hz

Now calculating the wavelength of the wave .

<u>Using </u><u>Formulae </u>

\boxed{ \bf \lambda =  \cfrac{v}{ \nu}}

Substituting the value and we obtain

\sf \longrightarrow \lambda \:  =  \cfrac{10}{0.1}  \\  \\  \\ \sf \longrightarrow \lambda \:  =   \cancel\cfrac{10}{0.1}  \\  \\  \\ \sf \longrightarrow \lambda \:  =100m

<u>Therefore</u><u>,</u>

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8 0
3 years ago
A bullet was fired from a gun. The bullet had a mass of 50g and the kinetic energy of the bullet was 25 kJ. How fast did it go?
Elenna [48]

Answer:

given \:  \\ mass \: (m) = 50g \\ kinetic \: enegy \: (k.e) = 25kj \\ velocity(v) = x \\ form \\ k.e =  \frac{1}{2}  \times MV ^{2}  \\ 25 =  \frac{1}{2}  \times 50 \times v {}^{2}  \\ 25 = 25 \times v {}^{2} \\ v {}^{2}  =  \frac{25}{25}  \\ v {}^{2}  = 1 \\ v =  \sqrt{1}  \\ v = 1ms {}^{ - }

the car it go fast with velocity 1m/s

5 0
3 years ago
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