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garik1379 [7]
3 years ago
12

An upward force of 32.6 N is applied via a string to lift a ball with a mass of 2.8 kg. (a) What is the gravitational force acti

ng on the ball? (b) What is the net force acting upon the ball? (c) What is the acceleration of the ball?
Physics
1 answer:
Igoryamba3 years ago
3 0

Answer:

a) Fg = -27.4 N

b) Fnet = 5.2 N

c) a = 1.9 m/s2

Explanation:

a)

  • There are two forces acting on the ball, one directed upward (assuming this direction as positive, along the y-axis) which is the tension on the string (lifting force), and another aimed downward, which is the attractive force due to gravity.
  • Applying the Newton's Universal Law of Gravitation to a mass close to the surface of the Earth (in this case the ball), we can take the acceleration due to gravity like a constant, that we call by convention g, equal to -9.8 m/s2.
  • So, we can write the following expression for Fg:

       F_{g} = m*g = 2.8 kg*(-9.8m/s2) = -27.4 N (1)

b)

  • The net force on the ball, will be just the difference between the lifting force (32.6 N) and the force due to gravity, Fg:

       F_{net} = T -F_{g} = 32.6 N - 27.4 N = 5.2 N  (2)

c)

  • According Newton's 2nd Law, the acceleration caused by a net force on a point mass (we can take the ball as one) is given by the following expression:

       a = \frac{F_{net} }{m} = \frac{5.2N}{2.8kg} = 1.9 m/s2  (3)

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Answer:

English        

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Los fenómenos eléctricos son eventos comunes e inusuales que se pueden observar y que iluminan los principios de la física de la electricidad y son explicados por ellos. Los fenómenos eléctricos son una división algo arbitraria de los fenómenos electromagnéticos.

6 0
3 years ago
Acartravelingat15m/sstartstodeceleratesteadily.Itcomestoacompletestopin10seconds.Whatisit'sacceleration? a. 1500 m/s b. -1.5 m/s
Amiraneli [1.4K]

Answer:

b. -1.5 m/s²

Explanation:

Given the following data;

Initial velocity = 15m/s

Time = 10 seconds.

Since the car came to rest, final velocity = 0m/s

To find acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of final speed from the initial speed all over time.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{initial \; speed  -  final \; speed}{time}

a = \frac{v  -  u}{t}

Where,

a is acceleration measured in ms^{-2}

v and u is initial and final speed respectively, measured in ms^{-1}

t is time measured in seconds.

Substituting into the equation, we have;

Acceleration, a = \frac{0 - 15}{10}

Acceleration, a = \frac{-15}{10}

Acceleration = -1.5 m/s²

6 0
3 years ago
Jumping up before the elevator hits. After the cable snaps and the safety system fails, an elevator cab free-falls from a height
noname [10]

Answer:

a)   I = 2279.5 N s , b) F = 3.80 10⁵ N, c)   I = 3125.5 N s  and d)  F = 5.21 10⁵ N

Explanation:

The impulse is equal to the variation in the amount of movement.

    I =∫ F dt = Δp

     I = mv_{f} - m v₀

Let's calculate the final speed using kinematics, as the cable breaks the initial speed is zero

   v_{f}² = V₀² - 2g y

   v_{f}² = 0 - 2 9.8 30.0

   v_{f} = √588

   v_{f} = 24.25 m/s

a) We calculate the impulse

   I = 94 24.25 - 0

   I = 2279.5 N s

b) Let's join the other expression of the impulse to calculate the average force

   I = F t

  F = I / t

  F = 2279.5 / 6 10⁻³

  F = 3.80 10⁵ N

just before the crash the passenger jumps up with v = 8 m / s, let's take the moments of interest just when the elevator arrives with a speed of 24.25m/s down and as an end point the jump up to vf = 8 m / n

c)     I = m v_{f} - m v₀

       I = 94 8 - 94 (-24.25)

       I = 3125.5 N s

d)     F = I / t

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7 0
3 years ago
A bowling ball has a mass of 6 kg. What happens to its momentum when its speed increases from 2 m/s to 4 m/s?
mash [69]

Answer:

B) The initial momentum is 12 kg*m/s, and the final momentum is 24 kg*m/s

Explanation:

The momentum of an object is given by the product between its mass (m) and its velocity (v):

p=mv

Let's apply this formula to calculate the initial momentum and final momentum of the ball:

- initial momentum:

p_i = m v_i = (6 kg)(2 m/s)=12 kg m/s

- Final momentum:

p_f = m v_f = (6 kg)(4 m/s)=24 kg m/s

So, the correct answer is

B) The initial momentum is 12 kg*m/s, and the final momentum is 24 kg*m/s

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