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Vladimir79 [104]
3 years ago
9

The figure below shows a shooting competition, where air rifles fire soft metal at distant targets

Physics
1 answer:
bekas [8.4K]3 years ago
6 0

Answer:

where is the figure?

Explanation:

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A 67.0 kg crate is being raised by means of a rope. Its upward acceleration is 3.50 m/s2. What is the force exerted by the rope
serious [3.7K]
<span>A 67.0 kg crate is being raised by means of a rope. Its upward acceleration is 3.50 m/s2. What is the force exerted by the rope on the crate? 

</span>Newton's Second Law<span> of Motion states, “The force acting on an object is equal to the mass of that object times its acceleration.” We calculate as follows:
</span>
F = ma = 67.0 kg (3.50 m/s^2) = 234.5 J
7 0
3 years ago
Is it true that mproving overall fitness may not be possible for people who have physical limitations.
OleMash [197]
That's not true people that have a broken leg use crutches and the constant lifting of their own body weight will help them gain muscle 
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4 years ago
What temperature is required to transfer waste heat to the environment for a heat engine to be 100 percent efficient?
OLEGan [10]
This can be seen as a trick question because heat engines can typically never be 100 percent efficient. This is due to the presence of inefficiencies such as friction and heat loss to the environment. Even the best heat engines can only go up to around 50% efficiency.
6 0
3 years ago
Read 2 more answers
In each cycle, a heat engine an input of 1940 J of heat and exhausts 1480 J of heat. What is the thermal efficiency?
AleksAgata [21]

Answer:

0.237 (23.7 %)

Explanation:

The thermal efficiency of an engine is given by:

\eta=\frac{W}{Q_{in}}

where

W is the useful work output of the engine

Q_{in} is the heat in input

Here we have:

Q_{in}=1940 J

and the work done is the total heat in input minus the heat exhausted:

W=1940 J - 1480 J=460 J

So, the efficiency is

\eta=\frac{460 J}{1940 J}=0.237 (23.7 %)

8 0
3 years ago
A block of gelatin is 120mm by 120mm by 40mm whrn unstressed. A force of 49N is applied tangentially to the upper surface causin
Inessa05 [86]

Answer:

The shearing stress is 10208.3333 Pa

The shearing strain is 0.25

The shear modulus is 40833.3332 Pa

Explanation:

Given:

Block of gelatin of 120 mm x 120 mm by 40 mm

F = force = 49 N

Displacement = 10 mm

Questions: Find the shear modulus, Sm = ?, shearing stress, Ss = ?, shearing strain​, SS = ?

The shearing stress is defined as the force applied to the block over the projected area, first, it is necessary to calculate the area:

A = 40*120 = 4800 mm² = 0.0048 m²

The shearing stress:

Ss=\frac{F}{A} =\frac{49}{0.0048} =10208.3333Pa

The shearing strain is defined as the tangent of the displacement that the block over its length:

SS=tan\theta =\frac{Displacement}{L}  =\frac{10}{40} =0.25

Finally, the shear modulus is the division of the shearing stress over the shearing strain:

Sm=\frac{10208.3333}{0.25} =40833.3332Pa

6 0
4 years ago
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