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saul85 [17]
3 years ago
12

A rectangular loop of wire with width w = 5 cm, length L = 10cm, mass m = 40 g, and resistance R = 20 mΩ has an initial velocity

v0 = 1 m/s to the right. It crosses from a region with zero magnetic field to a region with B = 2T pointing out of the page. How far does the loop penetrate into the magnetic field?
Physics
1 answer:
zhuklara [117]3 years ago
5 0

Answer:

The loop penetrate 4 cm into the magnetic field.

Explanation:

Given that,

Width w= 5 cm

Length L= 10 cm

mass m = 40 g

Resistance R = 20 mΩ

Initial velocity = 1 m/s

Magnetic field = 2 T

We need to calculate the induced emf

Using formula of emf

\epsilon=v_{0}Bw

Put the value into the formula

\epsilon =1\times2\times5\times10^{-2}

\epsilon =10\times10^{-2}\ volt

We need to calculate the current

Using Lenz's formula

i=\dfrac{\epsilon}{R}

i=\dfrac{10\times10^{-2}}{20\times10^{-3}}

i=5\ A

We need to calculate the force

Using formula of force

F=i(\vec{w}\times\vec{B})

F=iwB

Put the value into the formula

F=5\times5\times10^{-2}\times2

F=0.5\ N

We need to calculate the acceleration

Using formula of acceleration

a=\dfrac{F}{m}

Put the value in to the formula

a=\dfrac{0.5}{40\times10^{-3}}

a=12.5\ m/s^2

We need to calculate the distance

Using equation of motion

v^2=u^2+2as

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{0-1^2}{2\times(-12.5)}

s=0.04\ m

s=4\ cm

Hence, The loop penetrate 4 cm into the magnetic field.

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Answer:

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Explanation:

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