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2 years ago

Marta is selling a handmade necklace for $250

1 answer:

3 0

It looks as though A and B are the same, otherwise I would have said that the correct answer is either one of those two. What's the difference between the two?

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Rearrange y =1/2x+1to make x the subject.

ella [17]

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$y = \frac{1}{2} x + 1 \\$

Multiply sides by 2

$2 \times y = 2 \times ( \frac{1}{2} x + 1) \\$

$2y =( 2 \times \frac{1}{2} x) + (2 \times 1) \\$

$2y = x + 2$

$x + 2 = 2y$

Subtract sides 2

$x + 2 - 2 = 2y - 2$

$x = 2y - 2$

Done...

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3 0

2 years ago

Read 2 more answers

Write the equation of a rational function g(x) with vertical asymptotes at x = -3 and x = 3 , a horizontal asymptote at y = -4 a

Bezzdna [24]

Answer:

The equation for rational function for given asymptotes is

f(x)=(-4x^2-6)/{(x-3)(x+3)}

Step-by-step explanation:

Given:

vertical Asymptotes at x=3 and x=-3 and a horizontal asymptote at

y=-4 i.e parallel to x axis.

To find:

equation of a rational function i.e function in form p/q

Solution;

the equation should be in form of p/q

Numerator :denominator.

Consider f(x)=g(x)/h(x)

as vertical asymptote are x=-3 and x=3

denominator becomes, (x-3) and (x+3)

for horizontal asymptote to exist there should have same degrees in numerator and denominator which of '2'

when g(x) will be degree '2' with -4 as coefficient and dont have any real.

zero.

By horizontal asymptote will be (-4x^2 -6)

The rational function is given by

f(x)=g(x)/h(x)

={(-4x^2-6)/(x-3)(x+3)}.

3 0

2 years ago

[02.03]

SVEN [57.7K]

Answer:

2) Equation 1 and Equation 2 have the same number of solutions.

Step-by-step explanation:

The two given equations are

1) 15x + 6 = 41 and 2) 2x + 13 = 28

Solving both equations, we get

Solving (1) : 15x + 6 = 41 ⇒ 15x = 41 - 6 = 35

or, x = 35/15 ⇒ x = 7/3

Solving (2) : 2x + 13 = 28⇒ 2x = 28 - 13 = 15

or, x = 15/2 ⇒ x = 15/2

So, from above solutions we can say that Equation 1 and Equation 2 have the same number of UNIQUE solution.

6 0

2 years ago

During a recent eruption, the volcano spewed out copious amount of ash. One small piece of ash was ejected from the volcano with

nlexa [21]

For question number 1:The plot H = H(t) is the parabola and it reaches its maximum in the moment when exactly at midpoint between the roots t = 0 and t = 23. At that moment t = 23/2 or 11.5 seconds.
For question number 2:To find the maximal height, just simply substitute t = 11.5 into the quadratic equation. The answer would be 22.9.
For question number 3:H(t) = 0, or, which is the same as -16t^2 + 368t = 0.Factor the left side to get -16*t*(t - 23) = 0.t = 0, relates to the very start of the process, when the ash started its way up.The other root is t = 23 seconds, and it is precisely the time moment when the bit of ash will go back to the ground.

6 0

2 years ago

The length,AB of the rectangular lot is 1 foot less than two times its width, BC. If the perimeter of the rectangular lot 394 fe

r-ruslan [8.4K]

Answer:

$AB=131\ ft$