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Ksivusya [100]
3 years ago
11

A school is keeping track of the number of tickets remaining for its year-end festival. The table shows the number of sales for

the first, second, third, and fourth weeks of the month leading up to the festival. Which graph could represent the data shown in the table?
Day Tickets 1 | 800 2 | 371 3 | 182 4 | 78 Please explain. I am not sure how to solve these. Thanks so much!

Mathematics
2 answers:
aleksandrvk [35]3 years ago
8 0
All you have to do is plot the points. Your dependent variable is the ticket sales, so it has to be in the y-axis. The independent variable, days, would be the x-axis. All in all, you would be able to plot 4 points corresponding to the 4 pairs of data given. Then, just connect them to obtain a graph. I used MS Excel to make the graph shown in the figure :)

Sav [38]3 years ago
4 0

Basically its Graph D.

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Answer:

D to C

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The radius is half the diameter or the center point to the edge (circumference)

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A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,
guajiro [1.7K]

We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation A=45e^{-0.05t}.

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate A=15 and solve for t as:

15=45e^{-0.05t}

\frac{15}{45}=\frac{45e^{-0.05t}}{45}

\frac{1}{3}=e^{-0.05t}

Now we will switch sides:

e^{-0.05t}=\frac{1}{3}

Let us take natural log on both sides of equation.

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Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})

-0.05t\cdot (1)=\text{ln}(\frac{1}{3})

-0.05t=\text{ln}(\frac{1}{3})

t=\frac{\text{ln}(\frac{1}{3})}{-0.05}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}

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t=-(0-\text{ln}(3))\cdot 20

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6 0
3 years ago
Choose a system of equations with the same solution as the following system:
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Answer:

Option A.

Step-by-step explanation:

We are given 6x+2y =-6 ......(1) and 3x-4y=-18 .....(2)

Solving equations (1) and (2) we get

12x+3x =-30, ⇒x= -2 and from equation (1), 2y= -6-6(-2) =6, ⇒ y=3

Therefore, the solution for the given set of equations is x= -2 and y=3

A) Solving the equations 8x+4y = -4 ....... (3)and 17x+2y =-28, we get  

8x -34x = -4 -(-56) =52, ⇒-26x =52, ⇒x=-2 and from equation )(3), we get -16+4y =-4, ⇒ y=3

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Therefore, option A) will have the same solution. (Answer)

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