Answer:
To solve the above problem we will use the unitary method as follows
As estimated If £ 3 is equivalent to € 4
Then, £ 1 will be equivalent to = € \frac{4}{3}
£ 64.60 will be equivalent to = € \frac{4}{3} \times 64.60 = 1.3333 \times 64.60 = 86.1311
Now you have to round the answer up to 2 decimal points to get the final answer
€ 86.1311 ≈ € 86.13
Thus, £ 64.60 is approximately equal to € 86.13.
Step-by-step explanation:
hope this helps if not let me now
assuming you means k = log_2(3) [as log(2)3 is the same thing as 3log(2) due to multiplication being commutative]
given log(ab) = log(a) + log(b)
log_2(48) = log_2(3) + log_2(16)
To solve this problem we first call x = number of action figures, y = number of dolles. A system of two equations with two unknowns must be made to describe the problem. The system is the following:
(x + 1) + y = 13
1/2 * x = y.
Then solving the system we have that x = 8 and y = 4.
Since we know that the number of action figures is twice as many dolls plus one, then x = 8 + 1 = 9.
Thus,
dollos = 4
action figures = 9
Solution
-6x - 3y = 9 Add 6x to both sides
-6x + 6x - 3y = 9 + 6x
-3y = 9 + 6x Or more conventionally
-3y = 6x + 9 Divide by - 3
y = 6x/-3 + 9/-3
y = - 2x - 3
I'm not sure exactly what you're asking but 1×10^-5 is .00001. I could be interpreting your question wrong in which case I'm sorry.