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Ira Lisetskai [31]
4 years ago
8

Which of the following is a polynomial? A. 15X4 B. 4X2 +9x+12 C. 3- 2x D. 6x2 +2/X

Mathematics
1 answer:
Scilla [17]4 years ago
7 0

Answer:

C

Step-by-step explanation:

I answered the question already

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HELP ME Look at the photo,
allsm [11]

Answer:

I believe... x=12

Step-by-step explanation:

5x = 4x + 12

5x - 4x = x

therefore, x = 12

hope this helps :)

3 0
2 years ago
Use f’( x ) = lim With h ---> 0 [f( x + h ) - f ( x )]/h to find the derivative at x for the given function. 5-x²
beks73 [17]
<h2>Answer:</h2>

The derivative of the function f(x) is:

                 f'(x)=-2x

<h2>Step-by-step explanation:</h2>

We are given a function f(x) as:

f(x)=5-x^2

We have:

f(x+h)=5-(x+h)^2\\\\i.e.\\\\f(x+h)=5-(x^2+h^2+2xh)

( Since,

(a+b)^2=a^2+b^2+2ab )

Hence, we get:

f(x+h)=5-x^2-h^2-2xh

Also, by using the definition of f'(x) i.e.

f'(x)= \lim_{h \to 0} \dfrac{f(x+h)-f(x)}{h}

Hence, on putting the value in the formula:

f'(x)= \lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-(5-x^2)}{h}\\\\\\f'(x)=\lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-5+x^2}{h}\\\\i.e.\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2-2xh}{h}\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2}{h}+\dfrac{-2xh}{h}\\\\f'(x)=\lim_{h \to 0} -h-2x\\\\i.e.\ on\ putting\ the\ limit\ we\ obtain:\\\\f'(x)=-2x

      Hence, the derivative of the function f(x) is:

          f'(x)=-2x

3 0
3 years ago
Read 2 more answers
What is the radius and diameter of the following circle?
Tomtit [17]

Answer:

1. Volume of a cone: 1. V = (1/3)πr2h 2. Slant height of a cone: 1. s = √(r2 + h2) 3. Lateral surface area of a cone: 1. L = πrs = πr√(r2 + h2) 4. Base surface area of a cone (a circle): 1. B = πr2 5. Total surface area of a cone: 1. A = L + B = πrs + πr2 = πr(s + r) = πr(r + √(r2 + h2))

Step-by-step explanation:

1. Volume of a cone: 1. V = (1/3)πr2h 2. Slant height of a cone: 1. s = √(r2 + h2) 3. Lateral surface area of a cone: 1. L = πrs = πr√(r2 + h2) 4. Base surface area of a cone (a circle): 1. B = πr2 5. Total surface area of a cone: 1. A = L + B = πrs + πr2 = πr(s + r) = πr(r + √(r2 + h2))

3 0
3 years ago
Write an equation of a line in point slope form that has a slope of -3 and passes through the point (3, -4).
Nesterboy [21]

1) Point-slope form

(y-y1)=m(x-x1)

m= - 3,

point (3,-4), so x1 = 3, y1 = - 4.

(y+4)= -3(x- 3)

2)Point-slope form

(y-y1)=m(x-x1)

m= - 3/4,

point (4,5), so x1 = 4, y1 = 5.

(y-5)= - 3/4(x-4)

6 0
3 years ago
Solve for x- <br> 6x^2 + 36x + 54 = 0
lions [1.4K]

Answer:

-3

Step-by-step explanation:

6x^2+36x+54=0

First, you can factor out a 6:

6(x^2+6x+9)=0

Next, you can factor the quadratic:

6(x+3)^2=0

Since the only value of x that could set this equation equal to 0 is -3, that is the answer. Hope this helps!

5 0
3 years ago
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